MS SQL 2005 compare field containing square parenthesis

Question

I am using MS SQL Server 2005 (9.0.4035) and trying to find rows that contain the same data in a nvarchar(4000) field. The field contains xml that has both opening and closing square parentheses.

Here is sample data:
DataID Data
1 1
2 1
3 2]
4 2]
5 3[
6 3[

Using the 'like' operator I expected to get 3 matching pairs, but my problem is that row 5 and 6 do not match each other, I only get back that rows 1 & 2 match, and 3 & 4 match.

I know MS SQL 2005 added regular expression support in queries but I did not expect them to evaluate field data as a regular expression, which I think it is doing. Is there a mode that I need to enable to get the proper results?

Any help appreciated,
Ryan

Edit: Added sql statement used:

Select t1.DataID, t2.DataID From TestTable t1, TestTable t2
Where t1.DataID <> t2.DataID
and t1.Data like t2.Data

Edit: Answer
Using '=' operator works, but escaping the '[' does not.

Answer 1

Change your query to use = instead of LIKE and you'll get the results that you expect. SQL 2005 T-SQL won't do regex - you'd need to use CLR functions for that - but the LIKE statment does do pattern matching. '[' and ']' are reserved for the pattern matching in a like statment, and you'd have to escape them out if you intended for them to be equality matches.

See http://msdn.microsoft.com/en-us/library/ms179859.aspx for info on the LIKE statement.

Either of the 2 queries below solved the problem in my tests...

--using equals operator...
Select t1.DataID, t2.DataID From TestTable t1, TestTable t2
Where t1.DataID <> t2.DataID
and t1.Data = t2.Data

--using replace to add an escape character.
Select t1.DataID, t2.DataID From TestTable t1, TestTable t2
Where t1.DataID <> t2.DataID
and t1.Data like REPLACE(t2.Data, '[', '\[') escape '\'