Is there a regular expression to find two different words in a sentence?

Question

Is there a regular expression to find two different words in a sentence? Extra credit for an expression that works in MS Visual Studio 2008 :)

For example:

reg_ex_match(A, B, "A sentence with A and B") = true
reg_ex_match(C, D, "A sentence with A and B") = false

See also this related question

Answer 1

Try searching regexlib.

Answer 2

Why not use boolean logic, rather than a complicated regex?

Code not tested:

public bool reg_ex_match(Regex A, Regex B, string s) {
    return A.isMatch(s) && B.isMatch(s);
}

Update: This assumes A and B are defined with word boundaries:

Regex A = new Regex(@"\bA\b");

Answer 3

".*A.*B.*|.*B.*A.*" You can add spaces around the words A and B if you want proper words.

Answer 4

This is quite similar to the problem of "and" operator, see this question

Answer 5

.*A.*\s.*B.*|.*B.*\s.*A.*

Please note the use of the '+' between A and B. This is to ensure you match on separate A and B. If this is not a requirement, then Łukasz Lew's answer is correct.

UPDATE: Changed as per Bryan's excellent observation below. The above expression will recognize A separated from B (or vice versa) with at least one whitespace character (space, tab or line break) between the two regions of interest.

Answer 6

For real words:

\bA\b.+\bB\b|\bB\b.+\bA\b

Answer 7

you guys r wierd