The title says it all. All I really want is the equivalent of PHP's $_POST[], and after searching the web for an hour, I'm still nowhere closer.
+4
A:
Your HttpServletRequest object has a getParameter(String paramName) method that can be used to get parameter values. http://java.sun.com/javaee/5/docs/api/javax/servlet/ServletRequest.html#getParameter(java.lang.String)
Ryan Ahearn
2008-08-07 19:43:36
+3
A:
POST variables should be accessible via the request object: HttpRequest.getParameterMap(). The exception is if the form is sending multipart MIME data (the FORM has enctype="multipart/form-data"). In that case, you need to parse the byte stream with a MIME parser. You can write your own or use an existing one like the Apache Commons File Upload API.
McDowell
2008-08-07 19:47:30
+7
A:
Here's a simple example. I didn't get fancy with the html or the servlet, but you should get the idea.
I hope this helps you out.
<html>
<body>
<form method="post" action="/myServlet">
<input type="text" name="username" />
<input type="password" name="password" />
<input type="submit" />
</form>
</body>
</html>
Now for the Servlet
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class MyServlet extends HttpServlet {
public void doPost(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
String userName = request.getParameter("username");
String password = request.getParameter("password");
....
....
}
}
ScArcher2
2008-08-14 13:52:55
Shouldn't the servlet method should be doPost not doGet since you want it to run on the form POST not the GET?
MB
2008-09-17 11:06:44
Yeah you're right. I got in a hurry. I probably copied it and pasted it. I fixed it now though. Thanks!
ScArcher2
2008-09-17 13:48:33