views:

2294

answers:

15

Edit: I have looked at the answers code: NONE of them do what I want (I've checked). It would seem that there is no way to do what I want in native c#. I guess that's not a disaster just a shame given that .NET does support it (see accepted answer).

Thanks all.


I have c# code (part of a test framework that will never be run except under a debugger) like this who's point it to avoid actually catching the exception as that makes debugging the code in the unwound part of the stack a royal pain.

Bool bad = true;
try
{
   MightThrow();
   bad = false;
}
finally
{
   if(bad) DoSomeLoggingOnFailure();

   //// Does not catch!!!! 
   //// exception continues to unwind stack.

   //// Note that re throwing the exception is NOT
   //// the same as not catching it in the first place
}

is their a better way to do this?

A solution would have to behave exactly like that under the debugger with regards to un-caught exceptions. It would have to result in the only one first chance exception and the debugger breaking at the point that the exception was originally thrown, not in a catch block.

Specifically I need the debugger on un-caught exceptions to stop a in side MightThrow.

The following doesn't work because it fails to have the debugger break in the correct place

try { ... } catch { throw; }

And this doesn't work because it looses stack info (and also breaks in the wrong place).

try { ... } catch(Excption e) { throw e; }

I known that in D I could use a scope(failure) block

A: 

Simplyfy it to:

try
{
   MightThrow();
}
catch(Exception ex)
{
   DoSomethingOnFailure(ex);
   throw;
}
Chris Ballance
That is different from the original code. DoSomethingOnFailure() runs every time the block executes.
Randolpho
I forgot to change the clause from "finally" to "catch"
Chris Ballance
I took back my ding. :)
Randolpho
Thanks, I caught it right as you dinged me :-)
Chris Ballance
that catches the exception, finally does not
BCS
There is no "finally" in my code snippet
Chris Ballance
This solution doesn't retain the exception, which is something it sounds like he wants.
Beska
duly noted and updated per your comment
Chris Ballance
A: 

No, I think this is a common idiom the way you have it.

EDIT To be clear, the "catch" then "rethrow" strategies offer the same run-time semantics, however they change the experience when the VS debugger is attached. Tooling and maintenance is important; debugging often requires you to 'catch all first-chance exceptions' and if you end up with lots of 'spurious' first-chance exceptions due to catch-then-rethrow in your code, it really hurts the ability to debug the code. This idiom is about interacting well with the tooling, as well as clearly expressing the intent (you don't want to 'catch', decide can't handle, and rethrow, instead you just want to log that an exception did happen but let it pass on by).

Brian
I can't believe this is the accepted answer. That's as far from common as it gets
Randolpho
The first word is the important part.
BCS
No being the answer to "is there a better way to do this?"? The answer is a resounding yes! You are walking down a very slippery slope.
Randolpho
Sorry for yanking the accept but Greg Beech gave a better answer
BCS
No prob, you can do whatever you like, it's your question.
Brian
+24  A: 

How about this:

try
{
  MightThrow();
}
catch
{
  DoSomethingOnFailure();
  throw; // added based on new information in the original question
}

Really, that's all you did. Finally is for things that must run regardless of whether an exception occurred.

[Edit: Clarification]

Based on the comments you've been mentioning, you want the exception to continue being thrown without modifying its original stack trace. In that case, you want to use the unadorned throw that I've added. This will allow the exception to continue up the stack and still allow you to handle part of the exception. Typical cases might be to close network connections or files.

[Second edit: Regarding your clarification]

Specifically I need the debugger on un-caught exceptions to stop at the original point of the throw (in MightThrow) not in the catch block.

I would argue against ever breaking a best-practice (and yes, this is a best-practice for partially handling exceptions) to add some minor value to your debugging. You can easily inspect the exception to determine the location of the exception throw.

[Final edit: You have your answer]

kronoz has thoughtfully provided you with the answer you sought. Don't break best practices -- use Visual Studio properly! You can set Visual Studio to break exactly when an exception is thrown. Here's official info on the subject.

I was actually unaware of the feature, so go give him the accepted answer. But please, don't go trying to handle exceptions in some funky way just to give yourself a hand debugging. All you do is open yourself up to more bugs.

Randolpho
that catches the exception, finally does not
BCS
Oh, I see. I'll modify, then.
Randolpho
The location of the throw is about 10% of the info I want. The rest is the local vars in all those stack frames. Also I'm doing logging, not error recovery.
BCS
You could, I dunno... get the location from the stack trace and then, say, set a breakpoint at that location?
Randolpho
He just said he's logging this, not debugging. Also, the stacktrace can still be lost in a throw; depending on what kind of exception. In my test I threw a division by zero error, and it was lost on re-throw.
Adam Lassek
I +1ed kronoz for his answer but that has the unfortunate side effect of breaking regardless of *any* try/catch/finally blocks. It's to big a hammer. I gave Brian the Green Check as it seems the correct answer turns out to be a simple "NO"
BCS
It's not that hard to switch. You're breaking standards for a very niche benefit.
Randolpho
BCS - I added some extra details, you can fine-tune fc-exception catching to a certain degree, though it still may not be the ideal solution for you. I do recommend at least experimenting with them however as they can be very useful! :)
kronoz
@Randolpho - I'd be intrigued to see some referenced articles for these 'best practices' and 'standards' you keep talking about. IMHO, there aren't any, and the approach proposed in the question is fine, and I've explained why in my answer.
Greg Beech
Let's start with this one: http://msdn.microsoft.com/en-us/library/ms173162.aspx and I'll let you Google the rest.
Randolpho
A: 
try
{
   MightThrow();
}
catch
{
   DoSomethingOnFailure();
}
Andy Mikula
+7  A: 

What's wrong with:

try
{
   MightThrow();
}
catch
{
   DoSomthingOnFailure();
   throw;
}
Rowland Shaw
that catches the exception, finally does not
BCS
hence the throw to rethrow it (without trouncing the stacktrace)
Rowland Shaw
+2  A: 

Isn't this the same as:

try 
{
    MightThrow();
}
catch (Exception e) 
{
    DoSomethingOnFailure();
    throw e;
}

?

Dan Vinton
No... you lose the stack info when you throw the object. Better to just use throw since stack preservation is needed.
StingyJack
@StingyJack - Okay, you lose the stack info, but (other than for debugging/logging) you're not doing anything with that, right? Otherwise you're coupling your error handling to your stack...
Dan Vinton
As it happens, the code is /only/ debugging and logging code.
BCS
Ah... you may be stuck with the 'bad' flag then, unless you can debug/log in the catch block?
Dan Vinton
+7  A: 

For code that should only run on exceptions, use the catch block:

try
{
   MightThrow();
}
catch (Exception ex)
{
   // this runs only when there was an exception
   DoSomthingOnFailure();
   // pass exception on to caller
   throw; 
}
finally
{
   // this runs everytime
   Cleanup();
}
M4N
that catches the exception, finally does not and I don't want to. see edit.
BCS
@BCS: Yes...it "catches" the exception, but it's doing what you want because of the "throw" line in the catch block...which rethrows the exception with the original stack trace.
Beska
but the debugger will then break on the throw; line so it does not do what I want.
BCS
+4  A: 

This is what you want. It will only call this method when an error occurs, and the "throw" statement will re-throw the exception with the callstack intact.

try
{
   MightThrow();
}
catch
{
   DoSomthingOnFailure();
   throw;
}
Jon Tackabury
+3  A: 

A "finally" block that runs only on failure is called "catch" (with no parameters). :-)

Now, there is a small caveat. If you want to have a specialised "catch" case for a particular exception type and have a generic "catch" that works for all exceptions, you'll have to do a bit of a custom logic.

Thus, I would do something like:

  try
  {
    MightThrow();
  }
  catch(MyException ex)
  {
    // Runs on MyException
    MySpecificFailureHandler()
    // Since we have handled the exception and can't execute the generic
    // "catch" block below, we need to explicitly run the generic failure handler
    MyGenericFailureHandler()
  }
  catch
  {
    // Runs on any exception hot handled specifically before
    MyGenericFailureHandler()
    // If you want to mimic "finally" behavior and propagate the exception
    // up the call stack
    throw;
  }
  finally
  {
    // Runs on any failure or success
    MyGenericCleanupHandler();
  }
Franci Penov
a catch block catches the exception, a finally block does not. That difference the the only thing I'm interested in.
BCS
Technically, the "finally" block also "catches" the exception, as it is invoked when the exception occures. In the case of finally though, any exeption is implicitly rethrown, and for the catch you have to do it explicitly. Hence, the parameterless "throw", which generates "rethrow" IL instruction.
Franci Penov
the debugger breaks before the finally or after the catch.
BCS
That is correct. However, the exception still has the proper stack trace in it. I would strongly advise against writing code that tailors to the behavior of a particular debugger. It would be extremely easy to forget to set "bad" in your try block and get side effects due to the "finally" block.
Franci Penov
@Franci - turns out that finally does not catch the exception. It is technically completely different to a catch.
Daniel Earwicker
+11  A: 

If you're interested in the debugger simply stopping precisely where the exception occurred then have you considered first-chance exceptions?

If you open Tools|Exceptions then tick the Common Language Runtime Exceptions box, the debugger will stop at the point of exception regardless of any try/catch/finally blocks.

Update: You can specify the precise exception you wish to catch by expanding the [+] tree in the Exceptions dialog. Though of course it will fire every time any exception of the specified type[s] occur[s], you can switch it on and off at will even in the middle of a debugging session, so with judicious use of breakpoints you can get it to do your bidding. I used it successfully to get around the 'target of an invocation has thrown an exception' ball ache originating from using reflection to instantiate objects. Very useful tool in such circumstances. Also note the locals and stack trace should be firmly available as far as I recall (just did a quick test and they are available), so no problems there.

Of course if you want to log things then that is outside the scope of an IDE debugger; and in which case first-chance exceptions won't help you!

Give it a go at least; I found them very useful and they might be more appropriate for your issue than you think.

kronoz
I can't figure out a way to code it the way he wants to - you're right, the IDE has a way to do this already.
Knobloch
Maybe he's not happy that first chance stops at MightThrow() instead of some line inside MightThrow()??
Knobloch
It'll stop at the line inside MightThrow(). Unless it's in some proprietary 3rd party library, in which case he's asking the impossible!
kronoz
The impossible would be nice, but I can live with the merely difficult :)
BCS
Since my post is currently at the top of the list, I linked to your answer there. BCS should mark this as the accepted answer.
Randolpho
This answer is the best /practical/ solution. However the "fault block" solution is exactly the info I was looking for. I'd accept both if it were possible.
BCS
+2  A: 

Every example so far is losing the original StackTrace according to my tests. Here's a solution that should work for you.

private static void PreserveStackTrace(Exception exception)
{
  MethodInfo preserveStackTrace = typeof(Exception).GetMethod("InternalPreserveStackTrace",
    BindingFlags.Instance | BindingFlags.NonPublic);
  preserveStackTrace.Invoke(exception, null);
}

try
{
   MightThrow();
}
catch (Exception ex)
{
    DoSomethingOnFailure();
    PreserveStackTrace(ex);
    throw;
}
Adam Lassek
I rather suspect that it will still break in the wrong place (OTOH what you do solve is an issue I have wanted to solve in other places) +1
BCS
In that case I think you still need to clarify what problem you're trying to solve.
Adam Lassek
+2  A: 

How about only catching an exception that "MightThrow" does not throw?

Bool bad = true;
try
{
   MightThrow();
   bad = false;
}
catch (SomePrivateMadeUpException foo)
{ 
   //empty
}
finally
{
   if(bad) DoSomeLoggingOnFailure();   
}
jdisk
What's the point in that? Why bother with the catch block at all? You don't need one.
Greg Beech
Well,as far as I know C# insists on having at least one catch after the try block. (Seehttp://msdn.microsoft.com/en-us/library/0yd65esw.aspx )This is contrary to Java, where the catch part is optional. C#
jdisk
the catch block is optional in C#, http://msdn.microsoft.com/en-us/library/s7fekhdy.aspx
Lucas
+17  A: 

So, in .NET what you're asking for is theoretically possible, but it's not going to be easy.

CIL actually defines five types of exception handling block! The try, catch and finally ones you're used to in C#, and two others:

  • filter - similar to a catch block but can run arbitrary code to determine whether it wants to handle the error, rather than just matching on type. This block has access to the exception object, and has the same effect on the exception stack trace as a catch block.

  • fault - similar to a finally block, however it is only run when an exception occurs. This block does not have access to the exception object, and has no effect on the exception stack trace (just like a finally block).

filter is available in some .NET languages (e.g. VB.NET, C++/CLI) but is not available in C#, unfortunately. However I don't know of any language, other than CIL, that allows the fault block to be expressed.

Because it can be done in IL means not all is lost, though. In theory you could use Reflection.Emit to dynamically emit a function that has a fault block and then pass the code you want to run in as lambda expressions (i.e. one for the try part, one for the fault part, and so on), however (a) this isn't easy, and (b) I'm unconvinced that this will actually give you a more useful stack trace than you're currently getting.

Sorry the answer isn't a "here's how to do it" type thing, but at least now you know! What you're doing now is probably the best approach IMHO.


Note to those saying that the approach used in the question is 'bad practice', it really isn't. When you implement a catch block you're saying "I need to do something with the exception object when an exception occurs" and when you implement a finally you're saying "I don't need the exception object, but I need to do something before the end of the function".

If what you're actually trying to say is "I don't need the exception object, but I need to do something when an exception occurs" then you're half way between the two, i.e. you want a fault block. As this isn't available in C#, you don't have an ideal option, so you may as well choose the option that is less likely to cause bugs by forgetting to re-throw, and which doesn't corrupt the stack trace.

Greg Beech
So the answer is "you can, sort of"
BCS
@BCS - pretty much, yeah. The infrastructure is there to do it, but nothing I know of exposes it in a useful way.
Greg Beech
Great answer here!
Graphain
+2  A: 

Let me recap your requirements the way I understand them:

  1. You want some code that is run only when an exception is generated, in order to do some logging.
  2. You want to run your test framework under debugger and break at the point at which the exception is thrown.

To meet your first requirement, you should write the code the way everybody suggested - using parameterless catch and throw.

To meet your second requirement while using the parameterless catch, you could configure your debugger to break when an exception is throw, not only when there's an unhandled exception. I suspect you know how to do it, but I'll put it here for answer completeness: in VS you can do that in Debug -> Exception -> Common Language Runtime Exceptions -> check the Thrown checkbox.

If you know that your app throws a lot of handled exceptions, that might not be an option for you. At that point, your only choice left to meet your first requirement is to either write the code to use finally for exception logging purposes or look into the direct IL emitting route as Greg Beech suggests.

However, whether the finally code is being executed depends on the debugger you are using. In particular, VS will break on an unhadled exception before the finally is executed and will not let you continue. Thus, unless you detach from the process at that point, your logging code will never be executed. In other words, the second requirement will interfere with meeting the first requirement.

Franci Penov
this code may well run inside of another catch block some times and not others.
BCS
+1  A: 

You could encapsulate your logic in a custom class, something like:

    public  class Executor
{
    private readonly Action mainActionDelegate;
    private readonly Action onFaultDelegate;

    public Executor(Action mainAction, Action onFault)
    {
        mainActionDelegate = mainAction;
        onFaultDelegate = onFault;
    }

    public  void Run()
    {
        bool bad = true;
        try
        {
            mainActionDelegate();
            bad = false;
        }
        finally
        {
            if(bad)
            {
                onFaultDelegate();
            }
        }
    }

}

And use it as:

            new Executor(MightThrow, DoSomeLoggingOnFailure).Run();

Hope this helps.

Jaime Febres
I'd strip that down to a static but that's just a style thing. +1
BCS