How do you do a Remote HTTP Post (request) in CSharp?
i really needs this pls. :(
+4
A:
You can use WCF or create a WebRequest
var httpRequest = (HttpWebRequest)WebRequest.Create("http://localhost/service.svc");
var httpRequest.Method = "POST";
using (var outputStream = httpRequest.GetRequestStream())
{
// some complicated logic to create the message
}
var response = httpRequest.GetResponse();
using (var stream = response.GetResponseStream())
{
// some complicated logic to handle the response message.
}
bendewey
2009-02-13 19:37:41
+3
A:
I use this very simple class:
public class RemotePost{
private System.Collections.Specialized.NameValueCollection Inputs
= new System.Collections.Specialized.NameValueCollection() ;
public string Url = "" ;
public string Method = "post" ;
public string FormName = "form1" ;
public void Add( string name, string value ){
Inputs.Add(name, value ) ;
}
public void Post(){
System.Web.HttpContext.Current.Response.Clear() ;
System.Web.HttpContext.Current.Response.Write( "<html><head>" ) ;
System.Web.HttpContext.Current.Response.Write( string .Format( "</head><body onload=\"document.{0}.submit()\">" ,FormName)) ;
System.Web.HttpContext.Current.Response.Write( string .Format( "<form name=\"{0}\" method=\"{1}\" action=\"{2}\" >" ,
FormName,Method,Url)) ;
for ( int i = 0 ; i< Inputs.Keys.Count ; i++){
System.Web.HttpContext.Current.Response.Write( string .Format( "<input name=\"{0}\" type=\"hidden\" value=\"{1}\">" ,Inputs.Keys[i],Inputs[Inputs.Keys[i]])) ;
}
System.Web.HttpContext.Current.Response.Write( "</form>" ) ;
System.Web.HttpContext.Current.Response.Write( "</body></html>" ) ;
System.Web.HttpContext.Current.Response.End() ;
}
}
And you use it thusly:
RemotePost myremotepost = new RemotePost() ;
myremotepost.Url = "http://www.jigar.net/demo/HttpRequestDemoServer.aspx" ;
myremotepost.Add( "field1" , "Huckleberry" ) ;
myremotepost.Add( "field2" , "Finn" ) ;
myremotepost.Post() ;
Very clean, easy to use and encapsulates all the muck. I prefer this to using the HttpWebRequest and so forth directly.
BobbyShaftoe
2009-02-13 19:37:54
Why is this getting downvoted?
BobbyShaftoe
2009-02-13 20:15:34
If I'm reading this correctly, it doesn't actually post a form, but responds with a form that can be posted.
David
2009-02-13 20:24:50
CodeMonkey1
2009-02-13 22:17:49
+1
A:
HttpWebRequest HttpWReq =
(HttpWebRequest)WebRequest.Create("http://www.google.com");
HttpWebResponse HttpWResp = (HttpWebResponse)HttpWReq.GetResponse();
Console.WriteLine(HttpWResp.StatusCode);
HttpWResp.Close();
Should print "OK" (200) if the request was successful
John T
2009-02-13 19:42:41
Since the OP is doing a POST you should mention the request stream side as well.
bendewey
2009-02-13 20:11:31
+1
A:
Im using the following piece of code for calling webservices using the httpwebrequest class:
internal static string CallWebServiceDetail(string url, string soapbody,
int timeout) {
return CallWebServiceDetail(url, soapbody, null, null, null, null,
null, timeout);
}
internal static string CallWebServiceDetail(string url, string soapbody,
string proxy, string contenttype, string method, string action,
string accept, int timeoutMilisecs) {
var req = (HttpWebRequest) WebRequest.Create(url);
if (action != null) {
req.Headers.Add("SOAPAction", action);
}
req.ContentType = contenttype ?? "text/xml;charset=\"utf-8\"";
req.Accept = accept ?? "text/xml";
req.Method = method ?? "POST";
req.Timeout = timeoutMilisecs;
if (proxy != null) {
req.Proxy = new WebProxy(proxy, true);
}
using(var stm = req.GetRequestStream()) {
XmlDocument doc = new XmlDocument();
doc.LoadXml(soapbody);
doc.Save(stm);
}
using(var resp = req.GetResponse()) {
using(var responseStream = resp.GetResponseStream()) {
using(var reader = new StreamReader(responseStream)) {
return reader.ReadToEnd();
}
}
}
}
This can be easily used to call a webservice
public void TestWebCall() {
const string url =
"http://www.ecubicle.net/whois_service.asmx/HelloWorld";
const string soap =
@"<soap:Envelope xmlns:soap='about:envelope'>
<soap:Body><HelloWorld /></soap:Body>
</soap:Envelope>";
string responseDoc = CallWebServiceDetail(url, soap, 1000);
XmlDocument doc = new XmlDocument();
doc.LoadXml(responseDoc);
string response = doc.DocumentElement.InnerText;
}
Christian Ernst Rysgaard
2009-03-26 12:10:14
A:
The problem when beginning with high-level language like C#, Java or PHP is that people may have never known how simple the underground is in reality. So here’s a short introduction:
Rebol Tutorial
2009-08-16 21:11:49