Redirect stderr and stdout in a bash script

Question

I want to redirect both stdout and stderr of a process to a single file. How do I do that in bash?

Answer 1

do_something 2>&1 | tee -a some_file

This is going to redirect everything to file and print it to stdout.

Answer 2

bash your_script.sh 1>file.log 2>&1

1>file.log instructs the shell to send STDOUT to the file file.log, and 2>&1 tells it to redirect STDERR (file descriptor 2) to STDOUT (file descriptor 1).

Note: The order matters as liw.fi pointed out, 2>&1 1>file.log doesn't work.

Answer 3

You can redirect stderr to stdout and the stdout into a file:

some_command 1>file.log 2>&1

See http://tldp.org/LDP/abs/html/io-redirection.html

EDIT: changed the order as pointed out in the comments

Answer 4

Take a look here. Should be:

yourcommand &>filename

(redirects both stdout and stderr to filename).

Answer 5

LOG_FACILITY="local7.notice"
LOG_TOPIC="my-prog-name"
LOG_TOPIC_OUT="$LOG_TOPIC-out[$$]"
LOG_TOPIC_ERR="$LOG_TOPIC-err[$$]"

exec 3>&1 > >(tee -a /dev/fd/3 | logger -p "$LOG_FACILITY" -t "$LOG_TOPIC_OUT" )
exec 2> >(logger -p "$LOG_FACILITY" -t "$LOG_TOPIC_ERR" )

It is related: Writing stdOut & stderr to syslog.

It almost work, but not from xinted ;(

Answer 6

Curiously, this works:

yourcommand &> filename

But this gives a syntax error:

yourcommand &>> filename
syntax error near unexpected token `>'

You have to use:

yourcommand 1>> filename 2>&1