I want to capture output of a Perl program and display output data (string on screen) in a text box on C# Windows Form.
Here is my main C# code:
public partial class frmMain : Form
{
private Process myProcess = null;
public frmMain()
{
InitializeComponent();
}
public delegate void UpdateUIDelegate(string data);
private void btnRun_Click(object sender, EventArgs e)
{
myProcess = new Process();
ProcessStartInfo myProcessStartInfo = new ProcessStartInfo("perl.exe");
myProcessStartInfo.Arguments = "test.pl";
myProcessStartInfo.UseShellExecute = false;
myProcessStartInfo.RedirectStandardOutput = true;
myProcessStartInfo.WindowStyle = ProcessWindowStyle.Hidden;
myProcessStartInfo.CreateNoWindow = true;
myProcess.StartInfo = myProcessStartInfo;
myProcess.OutputDataReceived += new DataReceivedEventHandler(myProcess_OutputDataReceived);
myProcess.Start();
myProcess.BeginOutputReadLine();
}
void myProcess_OutputDataReceived(object sender, DataReceivedEventArgs e)
{
if (txtOutput.InvokeRequired)
{
UpdateUIDelegate updateDelegate = new UpdateUIDelegate(UpdateUI);
this.Invoke(updateDelegate, e.Data);
}
}
void UpdateUI(string data)
{
txtOutput.Text += data + "\r\n";
}
}
and code for test.pl:
my @a = qw{1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19};
my @b = qw{a b c d e f g h i j k l m n o p q r s };
print 'start' . "\n";
while ( my ( $item1, $item2) = ( splice (@a, 0, 1), splice (@b, 0, 1) ) ) {
print 'Item 1: ' . $item1 . "\n";
print 'Item 2: ' . $item2 . "\n";
warn 'Finish one item' . "\n";
sleep(1);
}
I have a problem is that the output data is only displayed on text box until the Perl has finished.
It's more interesting when I found that, If I do the same with a console application (C#) everything seems okay.
Here's the code for console application:
class Program
{
static void Main(string[] args)
{
Process myProcess = new Process();
ProcessStartInfo myProcessStartInfo = new ProcessStartInfo("perl.exe");
myProcessStartInfo.Arguments = "test.pl";
myProcessStartInfo.UseShellExecute = false;
myProcessStartInfo.RedirectStandardOutput = true;
myProcess.StartInfo = myProcessStartInfo;
myProcess.OutputDataReceived += new DataReceivedEventHandler(myProcess_OutputDataReceived);
myProcess.Start();
myProcess.BeginOutputReadLine();
Console.Read();
}
static void myProcess_OutputDataReceived(object sender, DataReceivedEventArgs e)
{
Console.WriteLine(e.Data);
}
}
I'm trying to figure out what happens with my form application but still not find any clue. One more thing is that I can not get warn message with windows form application.