I'm trying to write (what I thought would be) a simple bash script that will:
- run virtualenv to create a new environment at $1
- activate the virtual environment
- do some more stuff (install django, add django-admin.py to the virtualenv's path, etc.)
Step 1 works quite well, but I can't seem to activate the virtualenv. For those not familiar with virtualenv, it creates an activate
file that activates the virtual environment. From the CLI, you run it using source
source $env_name/bin/activate
Where $env_name, obviously, is the name of the dir that the virtual env is installed in.
In my script, after creating the virtual environment, I store the path to the activate script like this:
activate="`pwd`/$ENV_NAME/bin/activate"
But when I call source "$activate"
, I get this:
/home/clawlor/bin/scripts/djangoenv: 20: source: not found
I know that $activate
contains the correct path to the activate script, in fact I even test that a file is there before I call source
. But source
itself can't seem to find it. I've also tried running all of the steps manually in the CLI, where everything works fine.
In my research I found this script, which is similar to what I want but is also doing a lot of other things that I don't need, like storing all of the virtual environments in a ~/.virtualenv directory (or whatever is in $WORKON_HOME). But it seems to me that he is creating the path to activate
, and calling source "$activate"
in basically the same way I am.
Here is the script in it's entirety:
#!/bin/sh
PYTHON_PATH=~/bin/python-2.6.1/bin/python
if [ $# = 1 ]
then
ENV_NAME="$1"
virtualenv -p $PYTHON_PATH --no-site-packages $ENV_NAME
activate="`pwd`/$ENV_NAME/bin/activate"
if [ ! -f "$activate" ]
then
echo "ERROR: activate not found at $activate"
return 1
fi
source "$activate"
else
echo 'Usage: djangoenv ENV_NAME'
fi
DISCLAIMER: My bash script-fu is pretty weak. I'm fairly comfortable at the CLI, but there may well be some extremely stupid reason this isn't working.