http://madisonlane.businesscatalyst.com
I'm trying to get the div#sign-post to sit above the div#bottom. This works fine in all browsers except IE6 & IE7. Can anyone see what the problem is here?
Also IE6 is displaying an additional 198px to the top of div#bottom.
Looks to me like you have some malformed HTML in there. I tried counting, and perhaps I lost count of the opening and closing tags, but it looks like div#container isn't closed. Try running your page through a validator (such as W3C's HTML Validator, or something) and fixing some of the errors. That's helped me with these sorts of problems in the past. Good luck!
Agree with validator comment - validating usually helps. But, if it doesn't heres a few pointers for z-index in IE:
1) elements who's z-index you're manipulating should be on the same level ie. you should be setting the z-index of #bottom and #body
if this is not feasible then
2) IE sometimes wont apply the z-index correctly unless the elements ou are applying it to have a position:relative. Try applying that property to #bottom and #body (or #signpost)
let me know how that works out
Darko
I've recently had an ongoing problem displaying one layer above another. In my case I was programmatically creating two layers in Javascript, one for diaplaying a custom control and one for creating a full screen layer behind it. FF was fine, bu IE displayed the full screen layer always on top of everything else.
After numerous trawls over the interweb, trying everyone's suggestions, the only way I eventually get it working was to remove position: attributes from both layers, and tweak the margin-top: attribute until I got a satisfactory result.
A bit of a hash, but it works and it'll be fine until IE 8 sorts out all of the current bugs......
I just had this problem and the fix I found (thanks to Quirksmode) was to give the direct parent of the node you are trying to set a z-index of it's own z-index that is at less than the z-index of the node you are trying to set. Here is a quick example that should work in IE6
<html>
<head>
<style type="text/css">
#AlwaysOnTop {
background-color: red;
color: white;
width: 300px;
position: fixed;
top: 0;
z-index: 2;
}
#Header {
color: white;
width: 100%;
text-align: center;
z-index: 1;
}
</style>
</head>
<body>
<div id="Header">
<div id="AlwaysOnTop">This will always be on top</div>
</div>
<div id="Content">Some long amount of text to produce a scroll bar</div>
</body>
</html>
Most of the answers here are wrong; some work, but not for the reason they state. Here is some explanation.
This is how z-index should work according to the spec:
z-index value to any element; if you don't, it defaults to autoposition attribute different from the default static) with a z-index different from auto create a new stacking context. Stacking contexts are the "units" of overlapping; one stacking context is either completely above the another (that is, every element of the first is above any element of the second) or completely below it.z-index value have that value as a stack level, other elements inherit from their parents. The element with the higher stack level is displayed on top. When two elements have the same stack level, generally the one which is later in the DOM tree is painted on top. (More complicated rules apply if they have a different position attribute.)In other words, when two elements have z-index set, in order todecide which will show on top, you need to check if they have any positioned parents which also have z-index set. If they don't, or the parents are common, the one with the higher z-index wins. If they do, you need to compare the parents, and the z-index of the children is irrelevant.
So the z-value decides how the element is placed compared to other children of its "stacking parent" (the closest ancestor with a z-value set and a position of relative, absolute or fixed), but it doesn't matter when comparing to other elements; it is the stacking parent's z-value (or possibly the z-value of the stacking parent's stacking parent, et cetera) which counts. In a typical document where you use z-index only on a few elements like dropdown menus and popups, none of which contains the another, the stacking parent of all the elements which have a z-index is the whole document, and you can usually get away with thinking if the z-index as a global, document-level ordering.
The fundamental difference with IE6/7 is that poisitioned elements start new stacking contexts, whether they have z-value set or not. Since the elements which you would instinctively assign z-index values to are typically absolutely positioned and have a relatively positioned parent or close ancestor, this will mean that your z-index-ed elements won't be compared at all, instead their positioned ancestors will - and since those have no z-index set, document order will prevail.
As a workaround, you need to find out which ancestors are actually compared, and assign some z-index to them to restore the order you want (which will usually be reverse document order). Usually this is done by javascript - for a dropdown menu, you can walk through the menu containers or parent menu items, and assign them a z-index of 1000, 999, 998 and so on. Another method: when a popup or dropdown menu becomes visible, find all its relatively positioned ancestors, and give them an on-top class wich has a very high z-index; when it becomes invisible again, remove the classes.