Generate random values in C#

Question

How can I generate random Int64 and UInt64 values using the Random class in C#?

Answer 1

Use Random.NextBytes() and BitConverter.ToInt64 / BitConverter.ToUInt64.

// Assume rng refers to an instance of System.Random
byte[] bytes = new byte[8];
rng.NextBytes(bytes);
long int64 = BitConverter.ToInt64(bytes, 0);
ulong uint64 = BitConverter.ToUInt64(bytes, 0);

Note that using Random.Next() twice, shifting one value and then ORing/adding doesn't work. Random.Next() only produces non-negative integers, i.e. it generates 31 bits, not 32, so the result of two calls only produces 62 random bits instead of the 64 bits required to cover the complete range of Int64/UInt64. (Guffa's answer shows how to do it with three calls to Random.Next() though.)

Answer 2

This should do the trick. (It's an extension method so that you can call it just as you call the normal Next or NextDouble methods on a Random object).

public static Int64 NextInt64(this Random rnd)
{
    var buffer = new byte[sizeof(Int64)];
    rnd.NextBytes(buffer);
    return BitConverter.ToInt64(buffer, 0);
}

Just replace Int64 with UInt64 everywhere if you want unsigned integers instead and all should work fine.

Note: Since no context was provided regarding security or the desired randomness of the generated numbers (in fact the OP specifically mentioned the Random class), my example simply deals with the Random class, which is the preferred solution when randomness (often quantified as information entropy) is not an issue. As a matter of interest, see the other answers that mention RNGCryptoServiceProvider (the RNG provided in the System.Security namespace), which can be be used almost identically.

Answer 3

You could create a byte array, fill it with random data and then convert it to long (Int64) and ulong (UInt64).

byte[] buffer = new byte[sizeof(Int64)];
Random random = new Random();

random.NextBytes(buffer);
long signed = BitConverter.ToInt64(buffer, 0);

random.NextBytes(buffer);
long unsigned = BitConverter.ToUInt64(buffer, 0);

Answer 4

You don't say how you're going to use these random numbers...keep in mind that values returned by Random are not "cryptographically secure" and they shouldn't be used for things involving (big) secrets or (lots of) money.

Answer 5

I always use this to get my random seed (error checking removed for brevity):

m_randomURL = "https://www.random.org/cgi-bin/randnum?num=1&min=1&max=1000000000";
HttpWebRequest req = (HttpWebRequest)WebRequest.Create(m_randomURL);
StreamReader stIn = new StreamReader(req.GetResponse().GetResponseStream());
Random rand = new Random(Convert.ToInt32(stIn.ReadToEnd()));

random.org uses atmospheric noise to generate the randomness and is apparently used for lotteries and such.

Answer 6

You can use bit shift to put together a 64 bit random number from 31 bit random numbers, but you have to use three 31 bit numbers to get enough bits:

long r = rnd.Next();
r <<= 31;
r |= rnd.Next();
r <<= 31;
r |= rnd.Next();

Answer 7

Here you go, this uses the crytpo services (not the Random class), which is (theoretically) a better RNG then the Random class. You could easily make this an extension of Random or make your own Random class where the RNGCryptoServiceProvider is a class-level object.

using System.Security.Cryptography;
public static Int64 NextInt64()
{
   var bytes = new byte[sizeof(Int64)];    
   RNGCryptoServiceProvider Gen = new RNGCryptoServiceProvider();
   Gen.GetBytes(bytes);    
   return BitConverter.ToInt64(bytes , 0);        
}

Answer 8

Random r=new Random(); int j=r.next(1,23); Console.WriteLine(j);