Question regarding assembler output

Question

Consider the following assembler output:

START 100
MOVER BREG, ONE                                101) + 04 2 105 
MOVEM BREG, RESULT                             102) + 05 2 106
PRINT RESULT                                   103) + 10 0 106
STOP                                           104) + 00 0 000
ONE DC '1'                                     105) + 00 0 001
RESULT DS 1                                    106)

1. What does the + sign before code signifies?
2. Why the address of ONE is given 001?
3. Why the entry after the last RESULT DS 1 statement is left blank?

Note this is not homework - the questioner appears to be asking about something from a text book.

Answer 1

I don't know which assembler you are using (it might have beem sensible to give that information in your question) so these are not particularly well-informed answers:

1. Don't know - what does your assembler's manual say
2. It isn't - that's the value
3. DS just reserves some space

Edit: An assembler is a computer program that takes text containing assembly language and turns it into machine code. It can also produce output in human readble form, which is what the code you posted appears to be. The format of the human readble form is specific to the particular assembler (i.e. program) that you are using - it is not specific to the machine architecture the assembler emits machine code for.

Answer 2

This appears to be using the simple assembly language in Chapter 4 of Systems Program and Operation.

In the description of the opcode output, it says, "The sign is not a part of the instruction." A quick perusal of the text didn't reveal what it is part of, and all of the examples have "+" in that column.