views:

4404

answers:

2

Consider the following HTML. If I have a JSON reference to the <button> element, how can I get a reference to the outer <tr> element in both cases

<table id="my-table">
 <tr>
  <td>
   <button>Foo</button>
  </td>
  <td>
   <div>
    <button>Bar</button>
   </div>
  </td>
 </tr>
</table>

<script type="text/js">
 $('#table button').click(function(){
  //$(this).parent().parent() will work for the first row
  //$(this).parent().parent().parent() will work for the second row
  //is there a selector or some magic json one liner that will climb
  //the DOM tree until it hits a TR, or do I have to code this myself
  //each time?   
  //$(this).????
 });
</script>

I know I could special case each condition, but I'm more interested "however deep you happen to be, climb the tree until you find element X" style solution. Something like this, but more jQuery like/less-verbose

var climb = function(node, str_rule){
 if($(node).is(str_rule)){
  return node;
 }
 else if($(node).is('body')){
  return false;
 }
 else{
  return climb(node.parentNode, str_rule);
 }
};

I know about the parent(expr) method, but from what I've seen is allows you filter parents one level up and NOT climb the tree until you find expr (I'd love code example proving me wrong)

+8  A: 

The parents function does what you want:

$(this).parents("tr:first");
Seb
Hope you don't mind, I added a link to the documentation.
Paolo Bergantino
Absolutely, thanks! That's what "Edit other people's posts" permission is for ;)
Seb
Ha, that's funny. I wondered why Visual jQuery listed parent(expr) twice; turns out I totally spaced the s at the end.
Alan Storm
+6  A: 

Also, if you are using jQuery 1.3+ you can use the closest method

$(this).closest("tr");
bendewey