How to split string by ',' unless ',' is within brackets using Regex?

Question

EDIT: Can anyone help me out with a regular expression for a string such as this?:

[Header 1], [Head,er 2], Header 3

so that I can split this into chunks like:
[Header 1]
[Head,er 2]
Header 3

I have gotten as far as this:

(?<=,|^).*?(?=,|$)

Which will give me:
[Header 1]
[Head
,er 2]
Header 3

Thanks!!

Answer 1

Variations of this question have been discussed before.

For instance:

• http://stackoverflow.com/questions/328387/regex-to-replace-all-n-in-a-string-but-no-those-inside-code-code-tag

Short answer: Regular Expressions are probably not the right tool for this. Write a proper parser. A FSM implementation is easy.

Answer 2

Isn't it as simple as this?

(?<=,|^)(?:[^,]|\[[^[]*\])*

Answer 3

 (?<=,|^)\s*\[[^]]*\]\s*(?=,|$)

use the [ and ] delimiters to your advantage

Answer 4

\[.*?\]

Forget the commas, you don't care about them. :)

Answer 5

You could either use a regular expression to match the values inside the brackets:

\[[^\]*]\]

Or you use this regular expression to split the bracket list (using look-around assertions):

(?<=]|^)\s*,\s*(?=\[|$)

Answer 6

In this case it's easier to split on the delimiters (commas) than to match the tokens (or chunks). Identifying the commas that are delimiters takes a relatively simple lookahead:

,(?=[^\]]*(?:\[|$))

Each time you find a comma, you do a lookahead for one of three things. If you find a closing square bracket first, the comma is inside a pair of brackets, so it's not a delimiter. If you find an opening bracket or the end of the line/string, it's a delimiter.