Using SO_REUSEADDR - What happens to previously open socket?

Question

Hi Everyone, In network programming in unix, I have always set the SO_REUSEADDR option on the socket being used by server to listen to connections on. This basically says that another socket can be opened on the same port on the machine. This is useful when recovering from a crash and the socket was not properly closed - the app can be restarted and it will simply open another socket on the same port and continue listening.

My question is, what happens to the old socket? Without a doubt, all data/connections will still be received on the old socket. Does it get closed automatically by the OS?

Any help would be much appreciated.

Cheers

Answer 1

Yes, the OS automatically closes the previous socket when the old process ends. The reason you can't normally listen on the same port right away is because the socket, though closed, remains in the 2MSL state for some amount of time (generally a few minutes). The OS automatically transitions the old socket out of this state when the timeout expires.

Answer 2

A socket is considered closed when the program that was using it dies. That much is handled by the OS, and the OS will refuse to accept any further communication from the dead conversation. However, if the socket was closed unexpectedly, the computer on the other end might not know that the conversation is over, and may still be attempting to communicate.

That is why there is, designed into the TCP spec, a waiting period before that same port number can be reused. Because in theory, however unlikely, it may be possible for a packet from the old conversation to arrive with the appropriate IP address, port numbers, and sequence numbers such that the receiving server mistakenly inserts it into the wrong TCP stream by accident.

The SO_REUSEADDR option overrides that behavior, allowing you to reuse the port immediately. Effectively, you're saying: "I understand the risks and would like to use the port anyway."