Rotate a point by an angle

Question

I want to know how to work out the new co-ordinates for a point when rotated by an angle relative to another point.

I have a block arrow and want to rotate it by an angle theta relative to a point in the middle of the base of the arrow.

This is required to allow me to draw a polygon between 2 onscreen controls. I can't use and rotate an image.

From what I have considered so far what complicates the matter further is that the origin of a screen is in the top left hand corner.

Answer 1

If you are using GDI+ to do that, you can use Transform methods of the Graphics object:

graphics.TranslateTransform(point of origin);
graphics.RotateTransform(rotation angle);

Then draw the actual stuff.

Answer 2

I have nothing to say.

Answer 3

If you rotate point (px, py) around point (ox, oy) by angle theta you'll get:

p'x = cos(theta) * (px-ox) - sin(theta) * (py-oy) + ox
p'y = sin(theta) * (px-ox) + cos(theta) * (py-oy) + oy