PyQt - make window top level

Question

Hello, i need to make my window top level when i need. Code of creating window:

class Application(QtGui.QMainWindow):
    def __init__(self, parent=None):
        QtGui.QMainWindow.__init__(self, None, Qt.Tool | Qt.FramelessWindowHint)
        self.setFocusPolicy(Qt.StrongFocus)
        self.setAttribute(Qt.WA_QuitOnClose, True)

And when i need i do:

self.setWindowFlags(Qt.WindowStaysOnTopHint)

But after running this part of code my window hides... I don't know, where is it. But my program doesn't close! Help! How can i make my window top most at need moment?

Answer 1

Calling .show() or .raise() on your window should make it top focus.

And from the doc for setWindowFlags():

Note: This function calls setParent() when changing the flags for a window, causing the widget to be hidden. You must call show() to make the widget visible again..

I just wanted to add for anyone else who finds this question that the Qt doc for C++ is a very good resource even when using PyQt, just make sure you point to the version of the Qt C++ doc that applies to your version of PyQt (The latest PyQt is compiled against 4.4 if that is what you are using).