By code, how can I test if a hard disk drive is sleeping without waking it up

Question

Hello, I'm building a small app that gives me the free space available on my disks.

I would like to add a feature displaying the status of the disk, if it is sleeping or not for example. The OS is Windows.

How can this be done? The code should not have to wake the disk to find out, of course ;)

A solution in C# would be nice but I guess any solution will do...

Thank you for you help.

Answer 1

C++ solution (call GetDiskPowerState and it will iterate over physical drives until there are no more):

class AutoHandle
{
    HANDLE mHandle;
public:
    AutoHandle() : mHandle(NULL) { }
    AutoHandle(HANDLE h) : mHandle(h) { }

    HANDLE * operator & ()
    {
     return &mHandle;
    }

    operator HANDLE() const
    {
     return mHandle;
    }

    ~AutoHandle()
    {
     if (mHandle && mHandle != INVALID_HANDLE_VALUE)
      ::CloseHandle(mHandle);
    }
};


bool
GetDiskPowerState(LPCTSTR disk, string & txt)
{
    AutoHandle hFile = CreateFile(disk, 0, FILE_SHARE_READ|FILE_SHARE_WRITE, NULL, OPEN_EXISTING, 0, NULL);
    if (hFile && hFile != INVALID_HANDLE_VALUE)
    {
     BOOL powerState = FALSE;
     const BOOL result = GetDevicePowerState(hFile, &powerState);
     const DWORD err = GetLastError();

     if (result)
     {
      if (powerState)
      {
       txt += disk;
       txt += " : powered up\r\n";
      }
      else
      {
       txt += disk;
       txt += " : sleeping\r\n";
      }
      return true;
     }
     else
     {
      txt += "Cannot get drive ";
      txt += disk;
      txt += "status\r\n";
      return false;
     }
    }

    return false;
}

string 
GetDiskPowerState()
{
    string text;
    CString driveName;
    bool result = true;
    for (int idx= 0; result; idx++)
    {
     driveName.Format("\\\\.\\PhysicalDrive%d", idx);
     result = GetDiskPowerState(driveName, text);
    }
    return text;
}