Help with regexp replacing every second comma in the string...

Question

Hello,

I have a string of that displays like this....

1235, 3, 1343, 5, 1234, 1

I need to replace every second comma with a semicolon

i.e.

1235, 3; 1343, 5; 1234, 1

the string length will always be different but will follow the same pattern as the above i.e. digits comma space digits comma space, etc.

how can I do this with javascript? Is it possible?

Thanks, Mike

Answer 1

How about:

var regex = /(\d+),\s(\d+),\s/g;
var str = '1235, 3, 1343, 5, 1234, 1'; 
alert(str.replace(regex, '$1, $2; ')); // 1235, 3; 1343, 5; 1234, 1

Answer 2

'1235, 3, 1343, 5, 1234, 1'.replace(/([0-9]+),\s([0-9]+),\s/g, '$1, $2; ')

Answer 3

var s = '1235, 3, 1343, 5, 1234, 1';
var result = s.replace(/(,[^,]*),/g,"$1;");

Answer 4

"1235, 3; 1343, 5; 1234, 1".replace(/(.*?),(.*?),/g, "$1,$2;");

Answer 5

var myregexp = /(\d+,\s\d+),/g;
result = subject.replace(myregexp, "$1;");

Answer 6

var s='1235, 3, 1343, 5, 1234, 1';

s=s.replace(/([^,]+,[^,]+),/g,'$1;')

match anything that is not a comma, followed by a comma, followed by anything that is not a comma, and a comma.

replace everthing inside the parens (which doesn't include the last comma) with itself ('$1'), and add a semicolon in place of that comma.