Right answers have already been given, but just elaborating a bit.
Simulating your current situation:
SQL> declare
2 cursor cur_t
3 is
4 select ename
5 from emp
6 where deptno = 10
7 ;
8 v_texttoadd emp.ename%type;
9 v_string varchar2(100);
10 begin
11 open cur_t;
12 loop
13 fetch cur_t into v_texttoadd;
14 v_string := v_string || v_texttoadd;
15 exit when cur_t%notfound;
16 end loop
17 ;
18 dbms_output.put_line(v_string);
19 end;
20 /
CLARKKINGMILLERMILLER
PL/SQL-procedure is geslaagd.
Here MILLER is printed twice. By just switching the EXIT statement and the v_string assignment, you get the desired result:
SQL> declare
2 cursor cur_t
3 is
4 select ename
5 from emp
6 where deptno = 10
7 ;
8 v_texttoadd emp.ename%type;
9 v_string varchar2(100);
10 begin
11 open cur_t;
12 loop
13 fetch cur_t into v_texttoadd;
14 exit when cur_t%notfound;
15 v_string := v_string || v_texttoadd;
16 end loop
17 ;
18 dbms_output.put_line(v_string);
19 end;
20 /
CLARKKINGMILLER
PL/SQL-procedure is geslaagd.
However, your PL/SQL code becomes easier when using a cursor-for-loop. You can then skip the v_texttoadd variable and the number of lines in your loop decreases:
SQL> declare
2 cursor cur_t
3 is
4 select ename
5 from emp
6 where deptno = 10
7 ;
8 v_string varchar2(100);
9 begin
10 for r in cur_t
11 loop
12 v_string := v_string || r.ename;
13 end loop
14 ;
15 dbms_output.put_line(v_string);
16 end;
17 /
CLARKKINGMILLER
PL/SQL-procedure is geslaagd.
You can also use straight SQL to accomplish the job. An example with the SQL model clause, if you are on version 10g or higher:
SQL> select string
2 from ( select string
3 , rn
4 from emp
5 where deptno = 10
6 model
7 dimension by (rownum rn)
8 measures (ename, cast(null as varchar2(100)) string)
9 ( string[any] order by rn desc = ename[cv()] || string[cv()+1]
10 )
11 )
12 where rn = 1
13 /
STRING
-----------------------------------------------------------------------------------
CLARKKINGMILLER
1 rij is geselecteerd.
Regards,
Rob.