Can you register an existing instance of a type in the Windsor Container?

Question

In the Windsor IOC container is it possible to register a type that I've already got an instance for, instead of having the container create it?

Answer 1

There is a AddComponentInstance method on the Container's Kernel property.

From the Unit Tests:

[Test]
 public void AddComponentInstance()
 {
  CustomerImpl customer = new CustomerImpl();

  kernel.AddComponentInstance("key", typeof(ICustomer), customer);
  Assert.IsTrue(kernel.HasComponent("key"));

  CustomerImpl customer2 = kernel["key"] as CustomerImpl;
  Assert.AreSame(customer, customer2);

  customer2 = kernel[typeof(ICustomer)] as CustomerImpl;
  Assert.AreSame(customer, customer2);
 }

 [Test]
 public void AddComponentInstance_ByService()
 {
  CustomerImpl customer = new CustomerImpl();

  kernel.AddComponentInstance <ICustomer>(customer);
  Assert.AreSame(kernel[typeof(ICustomer)],customer);
 }

 [Test]
 public void AddComponentInstance2()
 {
  CustomerImpl customer = new CustomerImpl();

  kernel.AddComponentInstance("key", customer);
  Assert.IsTrue(kernel.HasComponent("key"));

  CustomerImpl customer2 = kernel["key"] as CustomerImpl;
  Assert.AreSame(customer, customer2);

  customer2 = kernel[typeof(CustomerImpl)] as CustomerImpl;
  Assert.AreSame(customer, customer2);
 }