In a similar way to using varargs in C or C++:
fn(a, b)
fn(a, b, c, d, ...)
views:
1186answers:
3Not having used Python much, this was my initial idea. Why has this answer been marked down?
CiscoIPPhone
2009-05-28 08:38:05
I didn't mark it down, but I would guess it is because it is simply not the answer, and the actual answer is no more complicated than passing an array
David Sykes
2009-05-28 08:49:22
An array isn't even a basic Python type. (Though you can import such a thing from the standard library.) If the answer had been 'pass a list' however that would have been less wrong, but still more work than the canonical way given in the accepted answer above.
Kylotan
2009-05-29 11:27:28
+17
A:
Yes.
def manyArgs(*arg):
print "I was called with", len(arg), "arguments:", arg
>>> manyArgs(1)
I was called with 1 arguments: (1,)
>>> manyArgs(1, 2,3)
I was called with 3 arguments: (1, 2, 3)
As you can see, Python will give you a single tuple with all the arguments.
unwind
2009-05-28 07:51:54
http://docs.python.org/tutorial/controlflow.html#more-on-defining-functions
Miles
2009-05-28 08:06:04
+16
A:
Adding to unwinds post:
You can send multiple key-value args too.
def myfunc(**kwargs):
# kwargs is a dictionary.
for k,v in kwargs.iteritems():
print "%s = %s" % (k, v)
myfunc(abc=123, def=456)
# abc = 123
# def = 456
And you can mix the two:
def myfunc2(*args, **kwargs):
for a in args:
print a
for k,v in kwargs.iteritems():
print "%s = %s" % (k, v)
myfunc2(1, 2, 3, banan=123)
# 1
# 2
# 3
# banan = 123
They must be both declared and called in that order, that is the function signature needs to be *args, **kwargs, and called in that order.
Skurmedel
2009-05-28 07:59:58