hi guys,
i have a jquery function that when clicked produces a set timeout on making a div visible.
however, if another option is selected during the settimeout length, i would like to know how to destroy this function and stoop anything else in it happening.
my current code is:
$(document).ready(function(){
$('li#contact').click(function() {
$('ul.image_display').css('display', 'none');
$('ul.projects').fadeOut().hide();
$('li#cv').removeClass('cur');
$('li#projects').removeClass('cur');
$('li#contact').addClass('cur');
$('ul.contact').fadeIn(function()
{
setTimeout( function()
{
$('ul.contact').fadeOut('slow');
}, 8000);
});
setTimeout(function() {
$('li#contact').removeClass('cur');
$('li#cv').addClass('cur');
$('ul.projects').fadeIn('slow');
$('ul.image_display').css('display', 'block');
}, 8625);
});
});
a bit cumbersome but works until this is clicked:
$(document).ready(function(){
$('#projects').click(function() {
$('li#cv').removeClass('cur');
$('ul.contact').fadeOut().hide();
$('#contact').removeClass('cur');
$('ul.projects').fadeIn('slow');
$('#projects').addClass('cur');
$('ul.image_display').css('display', 'block');
});
});
if the second is clicked just after the first than class 'cur' still comes up on li#cv after the set time.
Does this make sense!!!!????
Hope so!