C Prog.: Structure as argument of function!?

Question

I am trying to to create structure "Date of birth", and function that will assign values to the structure, and i am wondering is that possible to do that somehow like this:

(PS. I am constantly getting error "Argument list syntax error", for 2nd and 23th lines.)

#include <stdio.h>
void input (dob_st *);
int main ()
{
    typedef struct
    {
     int year;
     int month;
     int day;
    }
    dob_st;

    dob_st date;
    dob_st *p;
    p=&date;
    input (*p);
    printf("%02i.",p->day);
    printf("%02i.",p->month);
    printf("%i.",p->year);

    return 0;
}
void upis (dob_st *p)
{
    printf ("Date of birth:\nDay?\n");
    scanf ("%i",&(p->day));
    printf ("Month?\n");
    scanf ("%i",&(p->month));
    printf ("Year?\n");
    scanf ("%i",&(p->year));
}

Answer 1

I think you're getting this because the definition of dob_st is local only to main -- it's not defined outside this method. The void input (dob_st *); method has no way to know what the dob_st is, and it's called upis later on, not input, which is probably another error.

Answer 2

You're changing the name of the function from 'input' to 'upis'.

You also need to define dob_st outside the main() function.

Answer 3

p is a pointer, so the argument should be "input(p)" in stead of "inuput(*p)". Using *p deferenences the pointer, and it is not necessary in this case.

Answer 4

Some things: You should declare your structure outside of the main function, and before the prototype of the input function.

You should also pass to input a pointer to a dob_st structure and not a structure itself: The possible code now as

dob_st date;
dob_st *p;
p=&date;
input (*p);

should be

dob_st date;
input (&date);

and the output be later based on date directly.

PD: Is the upis function be meant to be the input function?

Answer 5

In standard C, you write "struct dob_st *p" instead of simply "dob_st *p". Also make sure that you declare the struct dob_st before you first use it.