if Expression

Question

hi, can any body tell me how to achieve following if expression in erlang

 if(a==b) {
           expression1
       }else {
           expression2 
       )

thanx in adavnce.

Answer 1

if
    a == b ->
        expr1;
    true ->
        exprElse
end 

There is no real else in Erlang, you just match with true. More information at the Erlang documentation.

You have to pay close attention to the ';' terminator :

if
    a == b ->
        clauseN,
        expr1;
    cond2 ->
        clause1,
        clause2,
        expr2;
    cond3 ->
        expr3;
    true ->
        exprElse
end 

It's not a copy-paste friendly language.

Answer 2

if
    a == b ->
        expr1;
    true ->
        expr2
end

or

case a == b of
    true -> expr1;
    false -> expr2
end

Answer 3

Pattern matching is one of Erlangs many strengths and it can often be used instead of if statements. It is often more readable to pattern match on function arguments or use a case expression (which also is pattern matching).

Suppose you have a function some_function which takes two arguments. If the arguments are equal you evaluate expression1, otherwise you evaluate expression2. This can be expressed in erlang as:

some_function(A, A) -> expression1;
some_function(A, B) -> expression2.

It is quite amazing how much you can achieve with this kind of simple pattern matching. With guard clauses you can express more complicated patterns, e.g.,

some_function(A, B) when A < B -> expression3.

Another possibility is to use a case .. of expression. Your particular example would translate to

case a == b of
    true -> expression1;
    false -> expression2
end.

(In this case expression2 would always be evaluated since a and b are atoms and never equal to each other. Variables in Erlang are upper case.)

You can read more about Erlang expressions here.

Answer 4

Another option:

case a of
    b -> expr1;  %% true
    _ -> expr2   %% false
end.