views:

1468

answers:

3

I have the following piece of HTML:

<div><p>Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor 
incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud 
exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in 
reprehenderit in voluptate velit <strong id="s">esse cillum dolore eu fugiat nulla pariatur.
Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum.</strong></p></div>

The width of the DIV is fixed at 600px using CSS. Now, I want to find the offset().left of the <strong> element. So I did:

alert( $("#s").offset().left );

However this does not seem to produce the right value, as I can clearly see the strong element is seen half way through the 600px width, but the offset value I get is only 8px.

How do I find the offset().left value of the inline strong element?

A: 

I believe offset is relative to the document, while position is relative to the parent.

http://docs.jquery.com/CSS/position

ScottE
+10  A: 
J-P
A (minor) optimization would be: 1. var pos = el.offset(); 2. el.remove(); 3: return pos; Instead of calling offset() twice and create a new object to return.
PatrikAkerstrand
Thanks Machine, just changed it :)
J-P
Best answer I've ever seen. Well done, J-P!
Patrick McElhaney
Great :) thanks!
philly77
Is there a reason why you’re using `.insertBefore(this[0])` and not just `.insertBefore(this)`?
Mathias Bynens
`this` could contain any number of elements, and since `offset()` only returns the offset of the first in the collection it would be pointless to insert before all of `this`.
J-P
@J-P Ah, of course, hadn’t thought of that! I see now :)
Mathias Bynens
A: 

The reason you are getting the result of 8px is because even though the element starts in half way through your container, since there's a line break its left edge is 8px in from the page.

I have one of those feelings that there's probably a much better way to do it than this, but the first thing I could think of to work around this problem is to insert another element right before the <strong> and check its position:

$("<span><span>").insertBefore($('#s')).offset();
nickf