Parsing string in Ruby

Question

I have a pretty simple string I want to parse in ruby and trying to find the most elegant solution. The string is of format /xyz/mov/exdaf/daeed.mov?arg1=blabla&arg2=3bla3bla

What I would like to have is : string1: /xyz/mov/exdaf/daeed.mov string2: arg1=blabla&arg2=3bla3bla

so basically tokenise on ?

but can't find a good example. Any help would be appreciated.

Answer 1

Split the initial string on question marks.

str.split("?")
=> ["/xyz/mov/exdaf/daeed.mov", "arg1=blabla&arg2=3bla3bla"]

Answer 2

This seems to be what youre looking for, strings built-in split function:

"abc?def".split("?") => ["abc", "def"]

Edit: Bah, to slow ;)

Answer 3

I think the best solution would be to use the URI module. (You can do things like URI.parse('your_uri_string').query to get the part to the right of the ?.) See http://www.ruby-doc.org/stdlib/libdoc/uri/rdoc/

Example:

002:0> require 'net/http'
true
003:0> URI
URI
004:0> URI.parse('/xyz/mov/exdaf/daeed.mov?arg1=bla&arg2=asdf')
#<URI::Generic:0xb7c0a190 URL:/xyz/mov/exdaf/daeed.mov?arg1=bla&arg2=asdf>
005:0> URI.parse('/xyz/mov/exdaf/daeed.mov?arg1=bla&arg2=asdf').query
"arg1=bla&arg2=asdf"
006:0> URI.parse('/xyz/mov/exdaf/daeed.mov?arg1=bla&arg2=asdf').path
"/xyz/mov/exdaf/daeed.mov"

Otherwise, you can capture on a regex: /^(.*?)\?(.*?)$/. Then $1 and $2 are what you want. (URI makes more sense in this case though.)