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1965

answers:

3

suppose a client starts a selenium session on an RC server, but at the middle of the session the client "went away". The browser will remain open, and eventually, after enough such dropped sessions, there will be enough "orphan" browsers to slow down the computer.

  • How can I make sure those browsers are closed?
  • Why isn't there a "keep-alive" part in the protocol to make sure the client is still responsive and if not kill the session?
  • +8  A: 

    Any browser instance has a session_id you can store. Python example:

    >>> import selenium
    >>> browser = selenium.selenium("localhost",4444, "*firefox", "http://www.santiycr.com.ar")
    >>> browser.start()
    >>> browser.sessionId
    u'b4ad1f1d624e44d9af4200b26d7375cc'
    

    So, if you store these sessionId in a file when your test starts and then remove it when your tests ends, you'll have a log file with sessions for tests that didn't end up properly.

    Now using cron, or any regular execution, you can read that file, iterate over the sessionIds stored in it and open the following url (using a browser or even an http library for your programing language):

    http://localhost:4444/selenium-server/driver/?sessionId=THE-SESSION-ID&cmd=testComplete

    That should do the trick.

    Edit: I found this question so interesting that created a post in my blog about the solution. If you're a python guy you'll find it interesting: http://www.santiycr.com.ar/djangosite/blog/posts/2009/aug/25/close-remaining-browsers-from-selenium-rc

    Santi
    Good Example Santi
    AutomatedTester
    A: 

    You can also just kill the process:

    Windows:

    taskkill /f /im iexplore.exe taskkill /f /im firefox.exe

    *nix:

    for i in ps -A | grep firefox | awk '{print $1}'; do kill -9 $i; done

    BotBilly
    this will kill all firefoxes, not just the "zombie" one. so if, for instance, you run two rc's on the same machine (not that unlikely), you might end up klling an ff that was used by the other RC.
    noam
    A: 
    >>> browser.stop()
    

    Does the same as Santi explains above.

    hruske