Let's say I have a directory like-
/home/user/
and I want to list EVERY file (even in sub directories) under that folder and order them by the date they were last edited.
Can I and if so, how?
Thanks!
+6
A:
You can use:
$ ls -Rt
where -R means recursive (include subdirectories) and -t means "sort by last modification date".
mipadi
2009-09-10 12:23:31
Thanks, that's perfect.I added a -l in there too so I can actually see the dates so for anyone who searches this out later, it's-$ ls -lRt
Marty
2009-09-10 12:27:50
If you're doing this at the prompt and want to see the most recently modified files, consider `ls -lrt[RhA]`. the `-r` reverses the sort order, leaving recently edited stuff at the bottom of the list...
dmckee
2009-09-10 12:59:39
+2
A:
If you'd like a master list in which all the files are sorted together by modification date, showing the directory they're in, but not grouped by directory, you can use this:
find . -type f -printf "%-.22T+ %M %n %-8u %-8g %8s %Tx %.8TX %p\n" | sort | cut -f 2- -d ' '
The result looks a lot like ls -l:
-rw-r--r-- 1 root root 3892 08/11/2009 11:03:36 /usr/share/man/man1/xmllint.1.gz -rw-r--r-- 1 root root 22946 08/13/2009 11:59:20 /usr/share/man/man1/curl.1.gz -rw-r--r-- 1 root root 728 08/17/2009 12:06:33 /usr/share/man/man1/thunderbird.1.gz -rw-r--r-- 1 root root 873 08/18/2009 10:52:47 /usr/share/man/man1/libgnutls-config.1.gz -rw-r--r-- 1 root root 2552 08/19/2009 02:00:34 /usr/share/man/man3/Purple.3pm.gz -rw-r--r-- 1 root root 9546 08/19/2009 02:02:00 /usr/share/man/man1/pidgin.1.gz -rw-r--r-- 1 root root 2201 08/19/2009 02:02:46 /usr/share/man/man3/Pidgin.3pm.gz -rw-r--r-- 1 root root 926 08/19/2009 02:03:05 /usr/share/man/man1/purple-remote.1.gz -rw-r--r-- 1 root root 18052 08/19/2009 04:11:47 /usr/share/man/man1/mono.1.gz -rw-r--r-- 1 root root 1845 08/19/2009 04:11:47 /usr/share/man/man5/mono-config.5.gz
Dennis Williamson
2009-09-10 14:36:45