tags:

views:

808

answers:

4

I'd like to wrap a css file in php... So I write the header for the css file and give it a php extension, thus... css.php. The question is will this work if the page is already being used as an include... or will this new header clash with the frame the page is being included into????

A: 

It will works if the includer script do not send any output, otherwise you will have an "Headers already sent" error.

using ob_start() in the includer can be a trick to avoid this and have everything work.

Html frames have nothing to do with php includes instead, so no conflict at all in this case.

AlberT
A: 

it's good practice to split your view and resouces. e.g.

homepage.php

<?php

echo '<link rel="stylesheet" type="text/css" href="css.php"/>';

?>

css.php

<?php

header('Content-Type: text/css');

echo 'body{background:#CCC;}';

?>

it will clash unless you split it apart

e.g.

homepage.php:

<?php

include('css.php');

?>

css.php:

<?php

if(isset($_GET['cssonly'])){
  header('Content-Type: text/css');
  echo 'body{background:#CCC;}';
  exit();
}

echo '<link rel="stylesheet" type="text/css" href="css.php?cssonly"/>';

?>
thephpdeveloper
So your saying... include('cssonly.php');cssonly is the php parsed file name or a name of a file I create???my css file name is inspiration.phpin your example... href="inspiration.php?cssonly";and cssonly is just part of the function???
hi there.. cssonly is a GET parameter. you were saying that your file was already being used as a include and CSS file. sorry i've realised i've got some errors. please read again.
thephpdeveloper
+4  A: 

If you have a file called css.php just make sure the first lines set the proper content-type header. You may also want to split your session setup stuff (if there is any) into a bootstrap.php if you haven't already. A quick example of loading some style info from a databse:

<?php 
  header("Content-Type: text/css"); 
  include('bootstrap.php');
  // fetch some information to print out our styles
  $result = mysql_query("SELECT * FROM site_styles");
  while ($row = mysql_fetch_assoc($result)) {
    echo $row["selector"]." {\n".$row["css"]."\n}\n";
  }
?>

From your other php file, just output the tag to include the css.php, you do not want to use the php include() function for this task!

<link rel="stylesheet" type="text/css" href="css.php"/>

Although since most browsers will cache your css file pretty aggressively, you might find that dynamically changing the contents of that file doesn't do much good. You could force that to update by adding a get parameter to the href of the link like so:

<link rel="stylesheet" type="text/css" href="css.php?<?php echo $cssversion ?>"/>

Although this is going to completely reload your css file every time that parameter changes. It is generally better practice to serve up static css files for this reason. If you have some styles that need to be loaded from configuration parameters, etc, that don't change very often, the first example should work for you quite well.

gnarf
A: 

gnarf nailed it.

I do:

    <link rel="stylesheet" type="text/css" media="screen" href="<? echo TMPL ?>css/name-of-file.css.php">

and then in top of your .css.php file:
<?
header('Content-Type: text/css');
// print out your php-driven css...
?>

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