I am afraid that there might be a situation for which the "greedy choice property" might not hold.
For any problem, I can only check for small data-sets. What if, for large data-sets, the property fails?
Can we ever be sure?
I am afraid that there might be a situation for which the "greedy choice property" might not hold.
For any problem, I can only check for small data-sets. What if, for large data-sets, the property fails?
Can we ever be sure?
A probably more theoretical way is the proof that your problem has a Matroid structure. If you can proof that your problem has such a structure, there is a greedy algorithm to solve it.
According to the classical book "Introduction to Algorithms" a matroid a is an ordered pair M = (S,l) with:
* S is a finite nonemtpy set
* l is a nonempty family of subsets of S, such that B element of l and
A a subset of B than also A is element of l. l is called the independent
subsets of S.
* If A and B are elements of l and A is a smaller cardinality than B, then
there is some element x that is in B, but not in A, so that A extended
by x is also element of l. That is called exchange property.
Often there is also a weight function w that assigns each element x in S, a weight.
If you can formulate your function as weighted matroid that the following Python-like pseudocode solves your problem:
GREEDY(M,w):
(S,l) = M
a = {}
sort S into monotonically decreasing order by weight w
for x in S:
if A + {x} in l:
A = A + {x}