counting in awk

Question

#!/bin/sh
find ${*-.} -type f -print | xargs file | 
awk '{
$1=NULL;
t[$0]++;
}
end {
for (i in t) printf("%d\t%s\n", t[i], i);
}' | sort -nr

The first "find" line works. But the awk part does not work. I expect the count of file types sorted in descending order.

Answer 1

awk is case sensitive - "end" should be "END"

Answer 2

Try to add a blank between the tick and the {:

awk ' {

Some versions of AWK need this.

Answer 3

Use END, not end.