So our app has the option to take either a picture or a video. If the user takes a picture, we can use the MediaStore.Images.Media.insertImage function to add the new image (via a filepath) to the phone's gallery and generate a content:// style URI. Is there a similar process for a captured video, given that we only have it's filepath?
                
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            I'm also interested, could you find a solution?
Edit: solution is RTFM. Based on the "Content Providers" chapter here is my code that worked:
        // Save the name and description of a video in a ContentValues map.  
        ContentValues values = new ContentValues(2);
        values.put(MediaStore.Video.Media.MIME_TYPE, "video/mp4");
        // values.put(MediaStore.Video.Media.DATA, f.getAbsolutePath()); 
        // Add a new record (identified by uri) without the video, but with the values just set.
        Uri uri = getContentResolver().insert(MediaStore.Video.Media.EXTERNAL_CONTENT_URI, values);
        // Now get a handle to the file for that record, and save the data into it.
        try {
            InputStream is = new FileInputStream(f);
            OutputStream os = getContentResolver().openOutputStream(uri);
            byte[] buffer = new byte[4096]; // tweaking this number may increase performance
            int len;
            while ((len = is.read(buffer)) != -1){
                os.write(buffer, 0, len);
            }
            os.flush();
            is.close();
            os.close();
        } catch (Exception e) {
            Log.e(TAG, "exception while writing video: ", e);
        } 
        sendBroadcast(new Intent(Intent.ACTION_MEDIA_SCANNER_SCAN_FILE, uri));
                  ber4444
                   2010-02-10 12:35:32
                
              
                
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            Possible duplicate of http://stackoverflow.com/questions/1925502/android-gallery-view-video-also-thumbnail-issues. I posted a response there.
                
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            Re: The solution posted. Note that Java has BufferedInputStream and BufferedOutputStream so you don't have to do that yourself.
                  Homer
                   2010-04-30 17:44:34