In python django how do you print out an object's inrospection? The list of all public methods of that object (variable and/or functions)?

Question

In python django how do you print out an object's inrospection? The list of all public methods of that object (variable and/or functions)?

e.g.:

def Factotum(models.Model):
  id_ref = models.IntegerField()

  def calculateSeniorityFactor():
    return (1000 - id_ref) * 1000

I want to be able to run a command line in the Django shell to tell me all of the public methods of a Django model. The output of running on above would be:

>> introspect Factotoum
--> Variable: id_ref
--> Methods: calculateSeniorityFactor

Answer 1

Well, things you can introspect are many, not just one.

Good things to start with are:

>>> help(object)
>>> dir(object)
>>> object.__dict__

Also take a look at the introspect module in the standard library.

That should make 99% of all the bases belong to you.

Answer 2

Use inspect:

import inspect
def introspect(something):
  methods = inspect.getmembers(something, inspect.ismethod)
  others = inspect.getmembers(something, lambda x: not inspect.ismethod(x))
  print 'Variable:',   # ?! what a WEIRD heading you want -- ah well, w/ever
  for name, _ in others: print name,
  print
  print 'Methods:',
  for name, _ in methods: print name,
  print

There's no way you can invoke this without parentheses in a normal Python shell, you'll have to use introspect(Factotum) ((with class Factotum property imported in the current namespace of course)) and not introspect Factotum with a space. If this irks you terribly, you may want to look at IPython.