How do I marshall a lambda (Proc) in Ruby?

Question

Joe Van Dyk asked the Ruby mailing list:

Hi,

In Ruby, I guess you can't marshal a lambda/proc object, right? Is that possible in lisp or other languages?

What I was trying to do:

l = lamda { ... }
Bj.submit "/path/to/ruby/program", :stdin => Marshal.dump(l)

So, I'm sending BackgroundJob a lambda object, which contains the context/code for what to do. But, guess that wasn't possible. I ended up marshaling a normal ruby object that contained instructions for what to do after the program ran.

Joe

Answer 1

Try ruby2ruby

Answer 2

You cannot marshal a Lambda or Proc. This is because both of them are considered closures, which means they close around the memory on which they were defined and can reference it. (In order to marshal them you'd have to Marshal all of the memory they could access at the time they were created.)

As Gaius pointed out though, you can use ruby2ruby to get a hold of the string of the program. That is, you can marshal the string that represents the ruby code and then reevaluate it later.

Answer 3

If you're interested in getting a string version of Ruby code using Ruby2Ruby, you might like this thread.

Answer 4

you could also just enter your code as a string:

code = %{
lamda {"hello, some ruby code".split(" ").each{|e| puts e + "!"}}
}

then execute it with eval

eval code

which will return a ruby lamda.

using the %{} format escapes a string, but only closes on an unmatched brace. i.e. you can nest braces like this %{ [] {} } and it's still enclosed.

most text syntax highlighters don't realize this is a string, so still display regular code highlighting.