How can I convert
ereg_replace(".*\.(.*)$","\\1",$imgfile);
to
preg_replace... ?
?
I'm having trouble with it?
views:
666answers:
2
+1
A:
delimiters, add any char to beginning and end of expression, in this case, and by tradition, the '/' character preg_replace('/.*\.(.*)$/',"\\1",$imgfile); The regex isn't very good, better to use strrpos and take substr().
Regex is slow, use this. $extension=substr($imgName,strrpos($imgName,'.'));
Jimmy Ruska
2010-03-14 21:47:17
I know but having this problem;preg_replace() [function.preg-replace]: Unknown modifier '$' in C:\wamp\www..
sml
2010-03-14 21:48:33
Yes, my bad, also the editing seems to destroy the expression. In the end better to use a substr() in this case. You could also use preg_match.
Jimmy Ruska
2010-03-14 21:52:30
You can escape your code with backticks (see http://stackoverflow.com/editing-help). The $ fix looks good.
Matthew Flaschen
2010-03-14 21:57:32
A:
preg_replace("/.*\.(.*)$/", "\\1", "foo.jpg")
I don't know why PHP requires the / delimiters. The only reason Perl, JS, etc. have them is that they allow regex literals, which PHP doesn't.
Matthew Flaschen
2010-03-14 21:49:26