C# Process <instance>.StandardOutput InvalidOperationException "Cannot mix synchronous and asynchronous operation on process stream.".

Question

I tried this

        myProcess = new Process();

        myProcess.StartInfo.CreateNoWindow = true;
        myProcess.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;

        myProcess.StartInfo.FileName = "Hello.exe";

        myProcess.StartInfo.Arguments ="-say Hello";
        myProcess.StartInfo.UseShellExecute = false;  

        myProcess.OutputDataReceived += new DataReceivedEventHandler(myProcess_OutputDataReceived);
        myProcess.ErrorDataReceived += new DataReceivedEventHandler(myProcess_OutputDataReceived);
        myProcess.Exited += new EventHandler(myProcess_Exited);
        myProcess.EnableRaisingEvents = true;

        myProcess.StartInfo.RedirectStandardOutput = true;
        myProcess.StartInfo.RedirectStandardError = true;
        myProcess.StartInfo.ErrorDialog = true;
        myProcess.StartInfo.WorkingDirectory = "D:\\Program Files\\Hello";

        myProcess.Start();

        myProcess.BeginOutputReadLine();
        myProcess.BeginErrorReadLine();

Then I am getting this error..

My process takes very long to complete, so I need to show progress in runtime.

Answer 1

You don't need to call ReadLine(), the line of text that was read is one of the properties passed to you in the DataReceivedEventArgs object.