How would I do something like below?
[
'foo'
['bar', 'baz'],
[
'one',
['two', 'three']
]
].each { |word| puts word }
# I want this to return:
foo
bar
baz
one
two
three
How would I do something like below?
[
'foo'
['bar', 'baz'],
[
'one',
['two', 'three']
]
].each { |word| puts word }
# I want this to return:
foo
bar
baz
one
two
three
The easiest way:
words = ['foo',['bar', 'baz'],['one',['two', 'three']]]
words.flatten.each{ |word| puts word }
Could you use flatten
?
[
'foo'
['bar', 'baz'],
[
'one',
['two', 'three']
]
].flatten.each { |word| puts word }
flatten
will return a copy of the array, so the original won't be modified.
It's also fully recursive so it doesn't matter how many arrays-within-arrays you have.
If you don't want to flatten the array and still achieve the desired functionality, you can do something like:
irb(main):016:0> array = [1, [2, 3], [4, [5, 6]]]
=> [1, [2, 3], [4, [5, 6]]]
irb(main):017:0> (traverser = lambda { |list| list.respond_to?(:each) ? list.each(&traverser) : puts(list) })[array]
1
2
3
4
5
6
=> [1, [2, 3], [4, [5, 6]]]