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Question

Pass a variable from view to the layout's partial view

Answer 1

+1 A:

I think there are multiple ways to handle this, here is one - not necessarily the best

<!-- layout -->
<body>
    <%= yield(:tabs_navigation) %>
    ...
</body>

<!-- views -->
<%- tabs_navigation(render :partial => "layouts/primary_menu", :locals => { :tab => "profiles" }) %>

another way - use a member variable instead of locals (this is kinda like cheating - but effective)

<!-- layout -->
<body>
    <%= render :partial => "layouts/primary_menu" %>
    ....
</body>

<!-- views -->
<%- @current_tab = "profiles" %>

now access the @current_tab directly in the primary_menu partial

Using content_for

<!-- layout -->
<body>
    <%= yield(:tabs_navigation) %>
    ...
</body>

<!-- views -->
<%- content_for :tabs_navigation do -%>
    <%= render :partial => "layouts/primary_menu", :locals => { :tab => "profiles" } %>
<%- end -%>

http://guides.rubyonrails.org/layouts_and_rendering.html#understanding-yield

house9 2010-05-07 19:40:53

Will :content_for work?

Craig 2010-05-07 20:48:02

added content_for example; pretty verbose when you just want to change the value of a single variable

house9 2010-05-07 22:21:36

Answer 2

A:

I decided to make use of the link_to_unless_current UrlHelper:

<%= link_to_unless_current "enroll", enroll_path, :class => "unselected" do
    link_to "enroll", enroll_path, :class => "selected"
end %>

Craig 2010-05-17 18:11:08

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answers:

Pass a variable from view to the layout's partial view

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