views:

51

answers:

3

I'm creating an SQL setup script and I'm using someone else's script as an example. Here's an example of the script:

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[be_Categories](
    [CategoryID] [uniqueidentifier] ROWGUIDCOL  NOT NULL CONSTRAINT [DF_be_Categories_CategoryID]  DEFAULT (newid()),
    [CategoryName] [nvarchar](50) NULL,
    [Description] [nvarchar](200) NULL,
    [ParentID] [uniqueidentifier] NULL,
 CONSTRAINT [PK_be_Categories] PRIMARY KEY CLUSTERED 
(
    [CategoryID] ASC
)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]
) ON [PRIMARY]
GO

Does anyone know what the ON [PRIMARY] command does? Regards.

+2  A: 

ON [PRIMARY] will create the structures on the "Primary" filegroup. In this case the primary key index and the table will be placed on the "Primary" filegroup within the database.

Mark S.
+2  A: 

It refers to which filegroup the object you are creating resides on. So your Primary filegroup could reside on drive D:\ of your server. you could then create another filegroup called Indexes. This filegroup could reside on drive E:\ of your server.

Barry
+3  A: 

When you create a database in Microsoft SQL Server you can have multiple file groups, where storage is created in multiple places, directories or disks. Each file group can be named. The PRIMARY file group is the default one, which is always created, and so the SQL you've given creates your table ON the PRIMARY file group.

See MSDN for the full syntax.

blowdart