A Ruby dev I know asked this; my answer is below... Are there other, better reasons?
Why do so many Ruby programmers do
"#{string}"
rather than
string
since the second form is simpler and more efficient?
A Ruby dev I know asked this; my answer is below... Are there other, better reasons?
Why do so many Ruby programmers do
"#{string}"
rather than
string
since the second form is simpler and more efficient?
Smaller changes when you later need to do more than simply get the value of the string, but also prepend/append to it at the point of use seems to be the best motivation I can find for that idiom.
Is this a common idiom for Ruby developers? I don't see it that much.
maybe it is easy way to convert any to string? Because it is the same as call to_s
method. But it is quite strange way :).
a = [1,2,3]
"#{a}"
#=> "123"
a.to_s
#=> "123"
What's the broader context of some of the usages? The only thing I can come up with beyond what's already been mentioned is as a loose attempt at type safety; that is, you may receive anything as an argument, and this could ensure that whatever you pass in walks like a duck..or, well, a string (though string.to_s
would arguably be clearer).
In general though, this is probably a code smell that someone along the way thought was Best Practices.
Interesting answers, everyone. I'm the developer who asked the original question. To give some more context, I see this occasionally at my current job, and also sometimes in sample code on the Rails list, with variables that are known in advance to contain strings. I could sort of understand it as a substitute for to_s, but I don't think that's what's going on here; I think people just forget that you don't need the interpolation syntax if you're just passing a string variable.
If anyone tried to tell me this was a best practice, I'd run away at top speed.
There is only one case where this is a recommended idiom :
fname = 'john'
lname = 'doe'
name = "#{fname} #{lname}"
The code above is more efficient than :
name = fname + ' ' + lname
or
name = [fname, lname].join(' ')