Reading non-standard elements in a SyndicationItem with SyndicationFeed

Question

With .net 3.5, there is a SyndicationFeed that will load in a RSS feed and allow you to run LINQ on it.

Here is an example of the RSS that I am loading:

<rss version="2.0" xmlns:media="http://search.yahoo.com/mrss/"&gt; 
<channel> 
    <title>Title of RSS feed</title> 
    <link>http://www.google.com&lt;/link&gt; 
    <description>Details about the feed</description> 
    <pubDate>Mon, 24 Nov 08 21:44:21 -0500</pubDate> 
    <language>en</language> 
    <item> 
     <title>Article 1</title> 
     <description><![CDATA[How to use StackOverflow.com]]></description> 
     <link>http://youtube.com/?v=y6_-cLWwEU0&lt;/link&gt; 
     <media:player url="http://youtube.com/?v=y6_-cLWwEU0" /> 
     <media:thumbnail url="http://img.youtube.com/vi/y6_-cLWwEU0/default.jpg" width="120" height="90" /> 
     <media:title>Jared on StackOverflow</media:title> 
     <media:category label="Tags">tag1, tag2</media:category> 
     <media:credit>Jared</media:credit> 
     <enclosure url="http://youtube.com/v/y6_-cLWwEU0.swf" length="233" type="application/x-shockwave-flash"/> 
    </item> 
</channel>

When I loop through the items, I can get back the title and the link through the public properties of SyndicationItem.

I can't seem to figure out how to get the attributes of the enclosure tag, or the values of the media tags. I tried using

SyndicationItem.ElementExtensions.ReadElementExtensions<string>("player", "http://search.yahoo.com/mrss/")

Any help with either of these?

Answer 1

Your missing the namespace. Using LINQPad and your example feed:

string xml = @"
    <rss version='2.0' xmlns:media='http://search.yahoo.com/mrss/'&gt; 
    <channel> 
        <title>Title of RSS feed</title> 
        <link>http://www.google.com&lt;/link&gt; 
        <description>Details about the feed</description> 
        <pubDate>Mon, 24 Nov 08 21:44:21 -0500</pubDate> 
        <language>en</language> 
        <item> 
            <title>Article 1</title> 
            <description><![CDATA[How to use StackOverflow.com]]></description> 
            <link>http://youtube.com/?v=y6_-cLWwEU0&lt;/link&gt; 
            <media:player url='http://youtube.com/?v=y6_-cLWwEU0' /> 
            <media:thumbnail url='http://img.youtube.com/vi/y6_-cLWwEU0/default.jpg' width='120' height='90' /> 
            <media:title>Jared on StackOverflow</media:title> 
            <media:category label='Tags'>tag1, tag2</media:category> 
            <media:credit>Jared</media:credit> 
            <enclosure url='http://youtube.com/v/y6_-cLWwEU0.swf' length='233' type='application/x-shockwave-flash'/> 
        </item> 
    </channel>
    </rss>
    ";



XElement rss = XElement.Parse( xml );
XNamespace media = "http://search.yahoo.com/mrss/";

var player = rss.Element( "channel" ).Element( "item" ).Element(media + "player").Attribute( "url" );
player.Dump();

result: url="http://youtube.com/?v=y6_-cLWwEU0"

The construct to look at is: Element(media + "player") that tells Linq to use the namespace represented by 'media' as well as the element name 'player'.

Brain damage must be setting in on my part, I thought you were using Linq. Anyway, you need to take the namespace into consideration.

Answer 2

You can use a combination of LINQ and XPathNavigator to extract the syndication extensions of a feed item (based on namespace URI of the extension). For item enclosures, you will want to examine the item links collection for links that have a RelationshipType of enclosure.

Example:

HttpWebRequest webRequest   = WebRequest.Create("http://www.pwop.com/feed.aspx?show=dotnetrocks&filetype=master") as HttpWebRequest;

using (Stream stream = webRequest.GetResponse().GetResponseStream())
{
    XmlReaderSettings settings  = new XmlReaderSettings();
    settings.IgnoreComments     = true;
    settings.IgnoreWhitespace   = true;

    using(XmlReader reader = XmlReader.Create(stream, settings))
    {
        SyndicationFeed feed    = SyndicationFeed.Load(reader);

        foreach(SyndicationItem item in feed.Items)
        {
            // Get values of syndication extension elements for a given namespace
            string extensionNamespaceUri            = "http://www.itunes.com/dtds/podcast-1.0.dtd";
            SyndicationElementExtension extension   = item.ElementExtensions.Where<SyndicationElementExtension>(x => x.OuterNamespace == extensionNamespaceUri).FirstOrDefault();
            XPathNavigator dataNavigator            = new XPathDocument(extension.GetReader()).CreateNavigator();

            XmlNamespaceManager resolver    = new XmlNamespaceManager(dataNavigator.NameTable);
            resolver.AddNamespace("itunes", extensionNamespaceUri);

            XPathNavigator authorNavigator      = dataNavigator.SelectSingleNode("itunes:author", resolver);
            XPathNavigator subtitleNavigator    = dataNavigator.SelectSingleNode("itunes:subtitle", resolver);
            XPathNavigator summaryNavigator     = dataNavigator.SelectSingleNode("itunes:summary", resolver);
            XPathNavigator durationNavigator    = dataNavigator.SelectSingleNode("itunes:duration", resolver);

            string author   = authorNavigator != null ? authorNavigator.Value : String.Empty;
            string subtitle = subtitleNavigator != null ? subtitleNavigator.Value : String.Empty;
            string summary  = summaryNavigator != null ? summaryNavigator.Value : String.Empty;
            string duration = durationNavigator != null ? durationNavigator.Value : String.Empty;

            // Get attributes of <enclosure> element
            foreach (SyndicationLink enclosure in item.Links.Where<SyndicationLink>(x => x.RelationshipType == "enclosure"))
            {
                Uri url             = enclosure.Uri;
                long length         = enclosure.Length;
                string mediaType    = enclosure.MediaType;
            }
        }
    }
}

Answer 3

Here is how I managed to retrieve the enclosure link from a feed using SyndicationFeed.

static void Main(string[] args)
{
    var feedUrl = "http://blog.stackoverflow.com/index.php?feed=podcast";

    using (var feedReader = XmlReader.Create(feedUrl))
    {
     var feedContent = SyndicationFeed.Load(feedReader);

     if (null == feedContent) return;

     foreach (var item in feedContent.Items)
     {
      Debug.WriteLine("Item Title: " + item.Title.Text);

      Debug.WriteLine("Item Links");
      foreach (var link in item.Links)
      {
       Debug.WriteLine("Link Title: " + link.Title);
       Debug.WriteLine("URI: " + link.Uri);
       Debug.WriteLine("RelationshipType: " + link.RelationshipType);
       Debug.WriteLine("MediaType: " + link.MediaType);
       Debug.WriteLine("Length: " + link.Length);
      }
     }
    }
}

The output is as follows:

Item Title: Podcast #50
Item Links
Link Title:
URI: http://blog.stackoverflow.com/2009/04/podcast-50/
RelationshipType: alternate
MediaType:
Length: 0
Link Title:
URI: http://itc.conversationsnetwork.org/audio/download/ITC.SO-Episode50-2009.04.21.mp3
RelationshipType: enclosure
MediaType: audio/mpeg
Length: 36580016

You can identify the enclosure link from its relationship type.

Answer 4

This should give you an idea on how to do it:

using System.Linq;
using System.ServiceModel.Syndication;
using System.Xml;
using System.Xml.Linq;

---

SyndicationFeed feed = reader.Read();

foreach (var item in feed.Items)
{
    foreach (SyndicationElementExtension extension in item.ElementExtensions)
    {
        XElement ele = extension.GetObject<XElement>();
        Console.WriteLine(ele.Value);
    }
}

Answer 5

Whether you're retrieving the non-XML contents of extension elements or XElement items, you might want to consider using a generic helper function like:

private static T GetExtensionElementValue<T>(SyndicationItem item, string extensionElementName)
{
       return item.ElementExtensions.Where(ee => ee.OuterName == extensionElementName).First().GetObject<T>();
}

Depending on whether the elements are guaranteed to be there or whether you are putting this into a reusable library, you may need to add additional defensive programming.