perl pattern match Downloaded: 1 files, 8.7K in 0s (16.9 MB/s)

Question

I have the following string "Downloaded: 1 files, 8.7K in 0s (16.9 MB/s)" which I got from wget and want to pattern match it by making a regular expression of it.

I tried with:

/^Downloaded: ([0-9]*) files, ([0-9GK]*) in ([0-9.]*)s ([0-9.]) [KM]B\/s/ 

But it does not work. I would appreciate any help. Thanks!

Answer 1

A character class like [0-9] only matches a single character. If you want one or more you should specify [0-9]+. Also, you forgot the dot in the character class for the size.

Also you could use \d+ instead of [0-9]+.

Answer 2

"Downloaded: 1 files, 8.7K in 0s (16.9 MB/s)"

does not match /^Downloaded: ([0-9]) files, ([0-9GK]) in ([0-9.]*)s ([0-9.]) [KM]B\/s/ because of the decimal point in "8.7K", and the parentheses around the download speed. Change that to:

/^Downloaded: (\d+) files, ([0-9.]+[GMK]) in ([0-9.]+)s \(([0-9.]+) [KM]B\/s\)/

I also made it so some of these values can have more than one digit, and you can have files that are in the megabyte range as well as kilobyte and gigabyte.