^[0-1]*1[0-1]*1[0-1]*1[0-1]*$
To match a binary string with 3 or more occurrences of '1' This expression works...just trying to make it better.
+1
A:
To match three or more occurrences of 1, I would use:
^(0*1){3}[01]*$
zebediah49
2010-08-01 23:36:18
Note that you can change that three to anything, and you get that many '1's in the matches.
zebediah49
2010-08-01 23:36:53
Sorry about confusion, my mistake i did mean at least 3 '1's
Dacto
2010-08-01 23:38:05
Change the last 0 to [01] and you're golden.
Mike DeSimone
2010-08-01 23:41:06
or use the `{3,}` syntax (means 3 or more)
glebm
2010-08-01 23:51:13