sed + match the first word in line and the second word that begin with abc

Question

How to match all lines that begins with word ADDRESS and the second string start with abc characters.

remark - ( I need to combine the sed syntax in my shell script)

for example

 more file

 ADDRESS abc1a (match)
 ADDRESS abc1b (match)
 ADDRESS acb1a (will not match)
 ADRESS  abc   (will not match)
 ADDRESS abc2a (will match)
 ADDRES  abc1a (will not match)
 ADDRESS ab    (will not match)

Answer 1

Why not just do:

grep '^ADDRESS abc' input_file

Answer 2

sed -n '/^ADDRESS[ \t]*abc/p' file

I suggest you show us your code next time since i believe you are quite familiar with ksh/sed/awk etc already.

Answer 3

Not a sed answer, but this is a clear translation of your requirements:

awk '$1 == "ADDRESS" && substr($2,0,3) == "abc"'