i have a list of a list:
b=[[1,2,3],[4,5,6],[7,8,9]]
i have a list:
row = [1,2,3]
how do i append to b
only row[0]
and '3847'
and row[2]
such that b
will equal:
b=[[1,2,3],[4,5,6],[7,8,9],[1,3847,3]]
i have a list of a list:
b=[[1,2,3],[4,5,6],[7,8,9]]
i have a list:
row = [1,2,3]
how do i append to b
only row[0]
and '3847'
and row[2]
such that b
will equal:
b=[[1,2,3],[4,5,6],[7,8,9],[1,3847,3]]
You're going to have to be more specific.
This will accomplish what you want:
b.append([row[0], 3847, row[2]])
But isn't really a general solution.
b + [row[0],3847,row[2]]
would give you:
>>> b + [row[0],3847,row[2]]
[[1, 2, 3], [4, 5, 6], [7, 8, 9], 1, 3847, 3]
In order to get b=[[1,2,3],[4,5,6],[7,8,9],[1,3847,3]]
, you need to use append
as suggested by "Nick Presta". You may have received other suitable solutions if you made the problem statement clearer.