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import itertools as it

list1=['12aa','2a','c2']
list2=['2ac','c2a','1ac']

# First- Finding combinations of each two item from list1.
first = list(it.combinations(list1, 2))

# Second- Finding combinations of each two item from list2.
second = list(it.combinations(list2, 2))

# Third- Finding combinations of each two items from list1 and list2
third = list(it.product(list1, list2))

# Fourth- Calculating each combinations total length
for combination in first: # first, second, third
    print combination, len(''.join(combination))

eumiro 2010-10-10 08:39:51

Actually, I want to produce combinations of each two item within a list and total characters in an individual combinations. Second, I want to produce combinations of each two items from list1 and list2 and total characters in an individual combinations.

2010-10-10 09:06:20

Exactly as you edited in your question.

eumiro 2010-10-10 09:09:42

Thank you so much, now I faced another problem. Suppose from our example list1 we got 3 combinations from three item. Now, I want to pass that individual combination into a function and want to know first item and second item for another operation but not messing up with previous problem

2010-10-10 10:24:38

Sorry, I don't quite understand your last comment. Could you just add an edit to your original question together with an example?

eumiro 2010-10-10 16:49:05

Is there any other way to do it without using combination? Because I figure out that when I try to run python file in other application terminal then it doesn't recognize combination(). Thank you

2010-10-10 19:58:46

If you are using Python older than 2.6, please check here: http://docs.python.org/library/itertools.html#itertools.combinations for a replacement function for combinations.

eumiro 2010-10-10 20:12:25

2010-10-11 08:07:21

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Finding length of items from a list

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