php code in jquery

Question

Hi, In CakePHP, the value passed as a parameter in the url can be obtained by the controller attribute

            <?php $userid= $this->params['pass'][0];?>

I want to use $userid inside the jQuery code.

 $("#displayPanel #saveForm").live("click", function(){

          document.location = 'http://localhost/cake_1_2/forms/homepage';

 });//Click on SaveForm

Suppose if the userid is 12, I need the document.location to be 'http://localhost/cake_1_2/forms/homepage/12'.

How to use the php variable in jQuery?

Answer 1

You'll need to output the variable into the JavaScript source:

$("#displayPanel #saveForm").live("click", function(){
          document.location = 'http://localhost/cake_1_2/forms/homepage/<?=$userid?>';
});//Click on SaveForm

Note the <?=$userid?>. If shorthand is turned off on your server, use <?php echo $userid; ?>.

Answer 2

For readability, how about:

<?php $userid= $this->params['pass'][0];?>
var userId = '<?=$userid?>';
$("#displayPanel #saveForm").live("click", function(){
    document.location = 'http://localhost/cake_1_2/forms/homepage/' + userId;
});