object Test extends Application {
// compiles:
Map[Int, Value](
0 -> KnownType(classOf[Object]),
1 -> UnknownValue())
// does not compile:
Map(
0 -> KnownType(classOf[Object]),
1 -> UnknownValue())
}
sealed trait Value {
def getType: Option[Class[_]]
}
case class UnknownValue() extends Value {
def getType = None
// compiles if changed to:
// def getType: Option[Class[_]] = None
}
case class KnownType(typ: Class[_]) extends Value {
def getType = Some(typ)
}
The above code fails to compile. The compiler's error message is:
Experiment.scala:10: error: type mismatch;
found : (Int, KnownType)
required: (Int, Product with Value{def getType: Option[java.lang.Class[_$2]]}) where type _$2
0 -> KnownType(classOf[Object]),
^
one error found
If I change the method declaration of UnknownValue to be def getType: Option[Class[_]] = None then also the Map() without type parameters compiles.
Why?