tags:

views:

513

answers:

6

Is there a function in Perl that lists all the files and directories in a directory? I remember that Java has the File.list() to do this? Is there a comparable method in Perl?

+2  A: 

this should do it.

my $dir = "bla/bla/upload";
opendir DIR,$dir;
my @dir = readdir(DIR);
close DIR;
foreach(@dir){
    if (-f $dir . "/" . $_ ){
        print $_,"   : file\n";
    }elsif(-d $dir . "/" . $_){
        print $_,"   : folder\n";
    }else{
        print $_,"   : other\n";
    }
}
Matthew Vines
You should check opendir for failure (opendir...or die "Error message: $!"). Also, am I missing something? What is Win32::GUI::DoEvents() doing here? (I don't see anything relevant in the question.)
Telemachus
+6  A: 

readdir() does that.

Check http://perldoc.perl.org/functions/readdir.html

opendir(DIR, $some_dir) || die "can't opendir $some_dir: $!";
@dots = grep { /^\./ && -f "$some_dir/$_" } readdir(DIR);
closedir DIR;
Vinko Vrsalovic
+10  A: 

Or use glob()

foreach $de (<*>) {
  print $de . "\n";
}

VolkerK
Remember you can't use <$pattern> --it is considered better form to use glob($pattern) instead (and the <*> operator uses glob internally, so there.) And don't forget File::Glob (which is part of the core distribution since 5.6.)
Leonardo Herrera
Absolutely right, it just _looks_ so much cooler (i.e. shorter) with foreach..(<*>) ;-)
VolkerK
For shortness, try perl -e '$\="\n"; print for <*>' or perl -e '$,=$\="\n"; print <*>' for 32 and 31 characters, respectively. Despite the golfing, ls is still about 16 times shorter. Don't do this in real code; if you do, local your changes to $\ and $,.
daotoad
Ditto on File::Glob. Without using File::Glob's version of glob(), files with spaces in their names are not handled properly.
Paul Chernoch
What about filenames with leading dots? perl -le 'chdir $ENV{HOME} or die; for (<*>) { print if /^\./ }'
Greg Bacon
+6  A: 

Or File::Find

use File::Find;
finddepth(\&wanted, '/some/path/to/dir');
sub wanted { print };

It'll go through subdirectories if they exist.

Todd Gardner
+3  A: 

If you want to get content of given directory, and only it (i.e. no subdirectories), the best way is to use opendir/readdir/closedir:

opendir my $dir, "/some/path" or die "Cannot open directory: $!";
my @files = readdir $dir;
closedir $dir;

You can also use:

my @files = glob( $dir . '/*' );

But in my opinion it is not as good - mostly because glob is quite complex thing (can filter results automatically) and using it to get all elements of directory seems as a too simple task.

On the other hand, if you need to get content from all of the directories and subdirectories, there is basically one standard solution:

use File::Find;

my @content;
find( \&wanted, '/some/path');
do_something_with( @content );

exit;

sub wanted {
  push @content, $File::Find::name;
  return;
}
depesz
A: 

This will list Everything (including sub directories) from the directory you specify, in order, and with the attributes. I have spent days looking for something to do this, and I took parts from this entire discussion, and a little of my own, and put it together. ENJOY!!

#!/usr/bin/perl --
print qq~Content-type: text/html\n\n~;
print qq~<font face="arial" size="2">~;

use File::Find;

# find( \&wanted_tom, '/home/thomas/public_html'); # if you want just one website, uncomment this, and comment out the next line
find( \&wanted_tom, '/home');
exit;

sub wanted_tom {
($dev,$ino,$mode,$nlink,$uid,$gid,$rdev,$size,$atime,$mtime,$ctime,$blksize,$blocks) = stat ($_);
$mode = (stat($_))[2];
$mode = substr(sprintf("%03lo", $mode), -3);

if (-d $File::Find::name) {
print "<br><b>--DIR $File::Find::name --ATTR:$mode</b><br>";
 } else {
print "$File::Find::name --ATTR:$mode<br>";
 }
  return;
}
Tom McAdams