Duplicate files with similar file names in UNIX

Question

I have a set of files in a single directory named:

OneThing-x.extension
OneThing-y.extension
OneThing-z.extension

What UNIX command (find, cp, xargs, sed ?) do I use to COPY these into

AnotherThing-x.extension
AnotherThing-y.extension
AnotherThing-z.extension

such that x ->copy-> x, and y ->copy -> y

I have the find .. part of the command to start with,which selects the files, but I am stuck there.

EDIT Obviously, I want to keep both the original and the copy, so a rename does not quite do the trick for me.

Answer 1

My rough solution would be something like:

for FIL in OneThing*; do NFIL=`echo $FIL|sed 's/OneThing/AnotherThing/'`; cp "$FIL" "$NFIL"; done;

Answer 2

Extending Jason Musgrove's solution:

for FIL in OneThing*
do
  NFIL=`echo $FIL | sed 's/OneThing/AnotherThing/'`
  cp "$FIL" "$NFIL"
done

Answer 3

$ rename 's/OneThing/AnotherThing/' *.extension

Answer 4

How about:

$ touch a1.a a2.a a3.a
$ ls

a1.a  a2.a  a3.a

$ for a in a*.a ; do cp $a $(echo $a | sed 's/^a/b/') ; done
$ ls

a1.a  a2.a  a3.a  b1.a  b2.a  b3.a

Answer 5

You could also use mmv:

$ mmv -c "OneThing*" "AnotherThing#1"

or

$ mmv -c "OneThing-*.extension" "AnotherThing-#1.extension"